1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katen [24]
3 years ago
13

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

ements best describes the electric field at a distance r from the electron? The electric field is directed toward the electron and has a magnitude of ke/r. The electric field is directed away from the electron and has a magnitude of ke/2. The electric field is directed toward the electron and has a magnitude of ke/? The electric field is directed toward the electron and has a magnitude of ke?/r. The electric field is directed away from the electron and has a magnitude of ke/r.
Physics
1 answer:
irina [24]3 years ago
4 0

Explanation:

The charge on the electron is, q=-1.6\times 10^{-19}\ C

The electric field at a distance r from the electron is :

E=k\dfrac{q}{r^2}

Where

k is the electrostatic constant, k=\dfrac{1}{4\pi \epsilon_o}

We know that the electric field lines starts from positive charge and ends at the negative charge. Also, for a positive charge the field lines are outwards while for a negative charge the field lines are inwards.

So, the correct option is " the  electric field is directed toward the electron and has a magnitude of k\dfrac{q}{r^2}. Hence, this is the required solution.

You might be interested in
Why is it important to listen to your body when playing sports
bonufazy [111]

Sometimes, you can play sport for a longer time than you should. You should always stop and take a little break and always drink water. Also, if something starts to hurt, stop, let someone responsible know and take a break.

4 0
4 years ago
Read 2 more answers
Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of
slamgirl [31]

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2

Substituting the velocities in the equation

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

5 0
3 years ago
An old manuscript reveals that a landowner in the time of King Arthur held 3.00 acres of plowed land plus a livestock area of 25
iragen [17]

Answer:

(a) Total area is 14.5 roods

(b) Total area is 14674.522 square meters

Explanation:

Area occupied by land = 3 acres

1 acre = 40 perches by 4 perches = 160 square perches

3 acres = 3×160 = 480 square perches

Area occupied by livestock = 25 perches by 4 perches = 100 square perches

Total area = 480 + 100 = 580 square perches

1 rood = 4 perches by 1 perch = 4 square perches

580 square perches = 580/4 = 14.5 roods

(b) Total area = 580 square perches

1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters

580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters

8 0
3 years ago
A 1,200 kg subcompact car accelerates at a rate of 3.0m/s
ludmilkaskok [199]
Missing question (found on internet): 
"what is the force of the car?"

Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
F=ma
For the car in the problem,
m=1200 kg
a=3.0 m/s^2
So the force that accelerates the car is
F=(1200 kg)(3.0 m/s^2)=3600 N
6 0
3 years ago
Is this class of lever a force- or distance magnifier?<br> Explain your answer.
Alekssandra [29.7K]
A force because the its pressure

4 0
4 years ago
Other questions:
  • A 33-kg girl is bouncing on a trampoline. During a certain interval after she leaves the
    8·1 answer
  • Two stars orbit each other in a _ solar system
    10·2 answers
  • The force in Newtons on a particle directed along the x-axis is given by F(x)=exp(−(x/5)+5) for x≥0 where x is in meters. The pa
    15·1 answer
  • For which property has Marvin forgotten to use an SI unit of measurement? A shore length B high temperature C low temperature D
    11·1 answer
  • A skier approaches the base of an icy hill with a speed of 12.5 m/s. The hill slopes upward at 24° above the horizontal. Ignorin
    12·1 answer
  • The following measurements are ranked from largest to smallest: 11.6 mg, 1021 µg, 0.000006 kg, 0.31 mg.
    13·1 answer
  • A mixture of nitrogen and water vapor at 200oF, 1 atm has the molar analysis of 80% N2, 20% water vapor.a) If the mixture is coo
    8·1 answer
  • Which of the following did not occur during the collapse of the solar nebula?
    12·1 answer
  • Consider the circular motion of a positively charged particle in the plane of this paper, due to a constant magnetic field B~ wh
    9·1 answer
  • the velocity of a car changes from 20 m/s east to 5 m/s east in 5 seconds. What is the acceleration of the car?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!