net ionic equation
B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
Explanation:
We have the following chemical equation:
2 Na⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 Cl⁻ (aq) → 2 Na⁺ (aq) + 2 Cl⁻ (aq) + BaSO₄ (s)
To get the net ionic equation we remove the spectator ions and we get:
SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
were:
(aq) - aqueous
(s) - solid
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net ionic equation
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Explanation:
Dissolve 93.52g of NaCl in about 400mL of distilled water, then add more water until final volume is 800mL. If starting with a solution or liquid reagent: When diluting more concentrated solutions, decide what volume(V2) and molarity (M2) the final soluble should be.
Answer:
they tend to be base
Explanation:
this because when they are manufactured they dont tend to use acid solution
Answer:
45.7kj
Explanation:
To calculates the heats of reaction from heats of formation:
∆Hr=£∆Hp -£∆Hr
= £∆Hch3ChOH - £∆HCh2h2+h20
=(-235.1kj)-(+52.47kj/kg + (-241.8kj/kg)
∆H = 45.71kj/kg
The balanced equations for the formation of potassium suberate from cyclooctene are;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
<h3>What is potassium suberate ?</h3>
The compound potassium suberate is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH
This is followed by the production of potassium suberate from the reaction equation;
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
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