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3 years ago

The plant on the left is growing more because it has been receiving more water

Chemistry

1 answer:

iVinArrow [24]3 years ago

3 0

Answer:

uhhh well ig btw what plant

Explanation:

it would be more sunlight to

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Filtering air to remove dust and pollen is it chemical or physical change

Cerrena [4.2K]

Answer:

Physical Change

Explanation:

Because the filter is removeing the dust by having the air go though a thin material.

Hope it helps!

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3 years ago

In which of these samples do the molecules most likely have the most kinetic energy?

hichkok12 [17]

Answer:

water vapor

Explanation:

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3 years ago

Question is in the picture

wariber [46]

Answer:

repelled

Explanation:

like charges repel one another

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4 years ago

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or

andrey2020 [161]

Answer:

The salt, LiNO₃ is a neutral, NR salt as it's a salt formed from the reaction of a strong acid and a strong base.In neutralisation reactions, acids and bases react to form salt and water.However, the salt formed may be acidic, basic or neutral. This is dependent on the type of acid and base which form the salt.A strong acid and a strong base react to yield a neutral salt like, LiNO₃.The equilibrium equation when LiNO₃ is dissolved in aqeous solution is;LiNO₃ + H2O ==>. LiOH + HNO₃

Explanation:

7 0

2 years ago

The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago