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taurus [48]
3 years ago
14

HURRY I NEED HELP

Chemistry
1 answer:
Andrews [41]3 years ago
8 0

Answer:

c

Explanation:

the shell is where the electrons are located and or orbit in a atom

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2.67 grams of butane (C4H10) is combusted in a bomb calorimeter. The temperature increases from 25.68 C to 36.2C. What is the ch
slavikrds [6]

The internal energy : 1310.43 kJ/mol

<h3>Further  explanation</h3>

Internal energy (ΔE) can be formulated for Calorimeter :

\tt \Delta E=C\times.\Delta t

C= the heat capacity of the calorimeter

Δt=36.2-25.68=10.52°C

\tt \Delta E=5.73 kJ/^oC\times 10.52^oC=60.2796~kJ

  • mol butane(MW=58,12 g/mol)

\tt \dfrac{2.67}{58,12 }=0.046

  • the internal energy (ΔE) in KJ/mol

\tt \dfrac{60.2796}{0.046}=1310.43~kJ/mol

7 0
3 years ago
Acetaldehyde shows two UV bands, one with a lmax of 289 nm ( 5 12) and one with a lmax of 182 nm ( 5 10,000). Which is the n p*
UkoKoshka [18]

Answer:

The bands are due to:

λmax = 289 nm n→π* transition (E = 12)

λmax = 182 nm π→π* transition (E=10000)

Explanation:

The two types of acetaldehyde transition are as follows:

n→π* and π→π*

From the attached diagram we have to:

ΔEn→π* < ΔEπ→π*

ΔEα(1/λ)

Thus:

λn→π* > λπ→π*

In n→π* spin forbidden, the intensity is low. Thus, the molar extinction E for n→π* is very low.

The same way, for π→π* spin allowed the intensity is high. Thus, the molar extinction coefficient E for π→π* is high too.

The bands are due to:

λmax = 289 nm n→π* transition (E = 12)

λmax = 182 nm π→π* transition (E=10000)

5 0
3 years ago
WILL GIVE BRANLIEST!!<br><br> Carbon tetrachloride (CCl4) is <br> ionic<br> covalent
monitta

Answer:

Covalent

Explanation:

In the carbon tetrachloride molecule, four chlorine atoms are positioned symmetrically as corners in a tetrahedral configuration joined to a central carbon atom by single covalent bonds

7 0
3 years ago
Read 2 more answers
Why are metals grouped together
Monica [59]
Because their atoms have the same number of electrons in the highest occupied energy level
5 0
4 years ago
10. A small gold nugget has volume of 0.87 cm3. What is its mass if the density of gold is 19.3 g/cm3?
bulgar [2K]

Answer:

16.791 grams

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange the formula for m, the mass. Multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass of the gold nugget can be found by multiplying the density and volume. The density is 19.3 grams per cubic centimeter and the volume is 0.87 cubic centimeters.

d= 19.3 g/cm^3\\v-0.87 cm^3

Substitute the values into the formula.

m=d*v

m= 19.3 g/cm^3*0.87 cm^3

Multiply. Note that the cubic centimeters, or cm³ will cancel each other out.

m=19.3 g*0.87

m=16.791 g

The mass of the gold nugget is 16.791 grams.

8 0
3 years ago
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