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3 years ago

An ancient silver coin has a density of 10.49 g/cm3 at 20°C. If you break the coin that weighs 4.001 in half

Chemistry

1 answer:

Wittaler [7]3 years ago

7 0

The density of each half of the coin is 10.49 g/cm3

In science density is defined as the ratio of mass to volume of an object.

Density is an intrinsic property.It is not affect by the amount of substance present.

This implies that each half of the broken coin must have the same density since it it is an inherent property of every silver material.

The density of each part of the coin therefore is 10.49 g/cm3.

Learn more: brainly.com/question/18320053

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You have 2.00 l of dry h2 at stp.how many moles is this

nalin [4]

V=2 L
Vm=22.4 L/mol

n=V/Vm

n=2/22.4=0.0893 mol

8 0

4 years ago

Theobromine (greek theobroma, meaning "food of the gods") is a common constituent in coca. fill in all the lone pairs on each he

Ganezh [65]

The lone pair of electrons in Theobromine are shown in RED color in attached figure.

Details:

In chemistry there are two types of electrons.

i) Bonding Pair Electrons:

These are those electrons which are being shared and are involved in making bonds. They are also called as sharing electrons. In given structure all the solid bonds either single or double are made up of bonding pair electrons.

ii) Lone Pair / Non-Bonding Pair Electrons:

Those electrons which doesn't take part in bonding and are not shared between atoms. In given structure the lone pair of electrons are found only on nitrogen atoms (single lone pair) and oxygen atoms (two lone pair of electrons) respectively.

Hybridization of Nitrogen Atoms;

N₁ = Sp²

N₂ = Sp³

N₃ = Sp³

N₄ = Sp³

Hybridization of Oxygen Atoms;

O₁ = Sp²

O₂ = Sp²

8 0

3 years ago

How are the Sun and Moon different? Compare and contrast these celestial bodies

iragen [17]

The sun is a luminous object while the moon is a non luminous object it only reflect the light from the sun... It takes 8.5 minutes for the light coming form the sun to reach the earth, it takes 1.3light seconds for the moon to reflect the light coming from the sun to the earth... The sun is a star while the moon is a satellite both the sun and the moon are round in shape... The sun has an outer temperature of about 6000°C while there is no breeze in the moon...

Comment for more....

7 0

4 years ago

The above reaction is run and found to follow second order kinetics with a rate constant of 1.30 x 10-3 M-1sec-1. If the initial

Leya [2.2K]

The final concentration after 172 seconds is 1.15 M. To obtain this answer, use the the integrated rate law for the order of reaction. Based on the problem, this is a second order reaction. The units of the rate constant also support that it is a second order reaction.

Further Explanation:

The solution to this problem is straightforward.

Identify the integrated rate law for the corresponding order of reaction.
Substitute the given values into the integrated rate law equation.
Use algebra to solve for the unknown, C(f).

STEP 1: Since the reaction is a second order reaction, the integrated rate law will be:

$\frac{1}{C_{f}} = \ kt \ + \frac{1}{C_{i}}$

where:

C(f) is the final concentration

k is the rate constant

t is the time

C(i) is the initial concentration

STEP 2: Plugging in the values given in the problem into the equation, the following equation should be obtained:

$\frac{1}{C_{f}} \ = (1.30 \ x \ 10^{-3} \frac{ \ 1 }{ \ M-s})(172 \ s) \ + \ \frac{1}{1.54 \ M} \\$

STEP 3: Using algebra to solve for C(f):

$\frac{1}{C_{f}} = \ 0.87295\\ \\C_{f} = \ 1.14554 \ M$

Since the given values only have 3 significant figures, the final answer must be expressed with 3 significant figures as well.

Therefore,

$\boxed {C_{f}\ = \ 1.15 \ M}$

Learn More

Learn more about half life brainly.com/question/4318844
Learn more about first order reaction brainly.com/question/8139015
Learn more about rate law brainly.com/question/1450796

Keywords: rate law, second order, integrated rate law

3 0

3 years ago

An element has a half-life of 5.0 days. How many days would

Olin [163]

Answer:

15 days

Explanation:

Given half-life = 5 days => k = 0.693/half-life = 0.693/5 days⁻¹

A = A₀e^-k·t => t = ln(A/A₀) / -k = ln(1/8) / -0.1386 days⁻¹ = 15 days

3 0

3 years ago