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3 years ago

ANSWER THIS QUESTION ASAP DONT SEND A FILE AT ALL. WHATS THE ANSWER HURYYY LIKE ANSWER THE QUESTION QUICK

Mathematics

2 answers:

Marina CMI [18]3 years ago

8 0

Answer: B

Step-by-step explanation:

Tems11 [23]3 years ago

5 0

The answer is B both are positive

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The answer in decimal form should be 5.3 if you round it up

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3 years ago

Find the value of x in the rectangle ABCD.

attashe74 [19]

Answer:

52°

Step-by-step explanation:

here's your solution

=> we know that the measure of angle of rectangle is 90°

=> 38° + X = 90°

=> X = 90° - 38°

=> X = 52°

hope it helps

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3 years ago

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Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

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3 years ago

A quadrilateral that has two pairs of Parallel sides and all sides congruent is a:

sweet-ann [11.9K]

Step-by-step explanation:

(square)+(rhombus)..............

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3 years ago

What are the coordinates of vertex J of the pre-image?(14 POINTS. PLS HELP, GEOMETRY)

DaniilM [7]

If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....

J is now (0, -2) multiply by 2
J was (0, -4)

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3 years ago

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