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3 years ago

14

3) Convection can only happen in what? *

1 answer:

otez555 [7]3 years ago

3 0

Answer:

Convection can only happen with liquids and gases.

Hope it helps :)

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What is the identity of an alpha particle?

Marianna [84]

Answer: It is a helium nuclei.

Explanation: Alpha particles are produced when a larger nuclei decays into smaller nuclei in radioactive decay. Alpha particles have mass number and atomic number as 4 and 2 respectively.

General representation of alpha decay :

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\textrm{He}$

7 0

3 years ago

Read 2 more answers

What is the approximate size of solute particles in a solution?

murzikaleks [220]

The approximate size of solute particles in a solution is 1 nanometer.

Explanation:

Solute and solvent are the two components required to prepare a solution. Solute is the one which is dissolved in the solvent to prepare a solution. So solute should be of lesser concentration compared to the solvent. Also the particle size of solute should be lesser in size compared to the solvent for easy diffusion and substitution. Mostly it is seen that if the solute is finer and having a size of less than 1 nanometer can be easily dissolved in the solvent.

So for forming homogeneous solutions, the solute is considered to be of materials having the particle size of 1 nanometer for perfect dissolving.

Thus, the approximate size of solute particles in solution is 1 nanometer.

7 0

4 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

3 years ago

g What is the relationship between the moles of the limiting reagent and the change in temperature (i.e. directly proportional o

ivann1987 [24]

Answer:

number of moles is inversely proportional to the Temperature

Explanation:

As we know

PV = nRT

where P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

If we see the equation, we can find that n is inversely proportional to the Temperature

5 0

3 years ago

Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have

Zepler [3.9K]

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

$1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}$

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

$m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g$

Thus, the price is:

$\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$$

Best regards!

7 0

4 years ago