All categories

3 years ago

List four ways of separate a mixture

Physics

1 answer:

KatRina [158]3 years ago

3 0

1.evaporation
2.fractional distillation
3.filtration
4.simple distillation

You might be interested in

A different force is applied to each of four different blocks on a frictionless, horizontal surface. In which diagram does the b

NeTakaya

Answer:

C. 4

Explanation:

6 0

3 years ago

A thin disk of mass 2.2 kg and radius 61.2 cm is suspended by a horizonal axis perpendicular to the disk through its rim. The di

Alinara [238K]

Answer: The period of the subsequent simple harmonic motion is 1.004 sec.

Explanation:

The given data is as follows.

Mass of disk (m) = 2.2 kg, radius of the disk (r) = 61.2 cm,

Formula to calculate the moment of inertia around the center of mass is as follows.

$I_{cm} = \frac{1}{2}mr^{2}$

= $\frac{1}{2} \times 2.2 kg \times (61.2)^{2}$

= 0.412 $kg m^{2}$

Also,

Distance between center of mass and axis of rotation (d) = r = 0.612 m

Moment of inertia about the axis of rotation (I)

I = $I_{cm} + md^{2}$

I = $0.412 + (2.2) \times (0.612)^{2}$

= 0.339 $kgm^{2}$

Now, we will calculate the time period as follows.

T = $2\pi sqrt{\frac{I}{mgd})$

T = $2 \times 3.14 sqrt{(\frac{0.339}{2.2 \times 9.8 \times 0.612}$

T = 1.435 sec

T = $2 \times 3.14 \times 0.16$

= 1.004 sec

Thus, we can conclude that the period of the subsequent simple harmonic motion is 1.004 sec.

7 0

3 years ago

What is the magnitude of the displacement of a car that travels half a lap along a circle of radius of 150m?

Lisa [10]

It would be equal to 2r = 2* 150 = 300m

6 0

3 years ago

A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the

Dvinal [7]

Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.

7 0

3 years ago

Can anyone solve this?

love history [14]

Answer:

F = 39.2 N

Explanation:

Since, the object is in uniform motion. Therefore, the frictional force on object will be:

Frictional Force = μk N = μk mg

where,

μk = coefficient of kinetic friction = 0.2

m = mass of crate = 10 kg

g = 9.8 m/s²

Therefore,

Frictional Force = (0.2)(10 kg)(9.8 m/s²)

Frictional Force = 19.6 N

The horizontal component of force must be equal to this frictional force to continue the uniform motion:

F Sin 30° = 19.6 N

F = 19.6 N/Sin 30°

3 0

3 years ago