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Arte-miy333 [17]
3 years ago
8

ok so i need a reasoning on What evidence have you discovered to explain how the curve of Earth’s surface affects temperatures o

n Earth?
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
3 0
The equator gets the most sun and has the warmest climate. This has to do with the tilt of the Earth on it’s axis. As you go north or south from the equator toward the poles the Earth’s temperature gets colder. It is harder for the sun’s direct rays & the curvature of the Earth to reach these points This has to do with the direct sunlight that reaches the equator. Think of a ball, or take a flashlight & shine it on a ball to see this yourself from different angles. The angle of the sun on the the Earth also causes different seasons.
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they had killed other animals

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How many oxygen atoms are present in a formula unit of calcium acetate?
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Help me with this question?!!​
olya-2409 [2.1K]

Answer:

500 mL

Explanation:

Step 1: Find conversions

1 mL = 0.0338 oz

Step 2: Use Dimensional Analysis

16.9 \hspace{2} oz(\frac{1 \hspace{2} mL}{0.0338 \hspace{2} oz} ) = 500 mL

3 0
3 years ago
In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe
const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = 10^{-9} m.

Hence, 0.283 nm = 0.283 \times 10^{-9} m

  • Formula for coulombic energy is as follows.

             U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}

where,   e = 1.6 \times 10^{-19} C

            \epsilon_{o} = 8.85 \times 10^{-12}

          U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}

                         = 1.423 \times 10^{-18} J

  • As 1 eV = 1.6 \times 10^{-19} J

So,       1 J = \frac{1 eV}{1.6 \times 10^{-19}}

Hence,    U = \frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}

                   = 8.9 eV

  • Also,   1 J = \frac{10^{-3} kJ}{6.022 \times 10^{23}mol}

                = 1.67 \times 10^{-27} kJ/mol

Therefore, U = 1.423 \times 10^{-18} J \times 1.67 \times 10^{-27} kJ/mol

                     = 2.37 \times 10^{-45} kJ/mol

7 0
3 years ago
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