Answer:
The answer is b. Carbon Tetrachloride
Explanation:
Let's discard the other options:
a. It couldn't be carbon chloride because there are four (4) chloride ions in the molecular formula. The molecular formula for the carbon chloride must be CCI. So, this answer is wrong
c. It could be monocarbon tetrachloride because there are 4 chloride ions and 1 carbon ion, but it's not necessary to use the prefix "mono" because there is just one carbon ion in the formula. In that way, when we mention carbon in the name, there is implicit that there is just one carbon atom in the formula. So, this answer could be ok, but isn't the best.
d. It couldn't be calcium chloride because there isn't any calcium ion or atom in the formula. The molecular formula for the calcium chloride must be CaCI. So, this answer is wrong
Answer:
4. 1.18 mol·L⁻¹
14. See below.
Explanation:
4. Dilution calculation
V₁c₁ = V₂c₂
Data:
V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹
V₂ = 950 mL; c₂ = ?
Calculation:
c₂ = c₁ × V₁/V₂
c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹
The new concentration is 1.18 mol·L⁻¹
.
14. Boyle's Law graphs
We can write Boyle's Law as
pV = k or p = k/V or V= k/p
p and V are inversely related.
(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.
(b) p = k/V =k(1/V)
1/V = (1/k)p
y = m x + 0
A graph of 1/V vs p is a straight line.
2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O
m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}
m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)
m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g
131.7 grams of carbon dioxide would be formed
