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sveta [45]
3 years ago
6

A garden hose fills a 2-gallon bucket in 5 seconds. The number of gallons, g (y), is proportional to the number of seconds, t (x

), that the water is running. What is the constant of proportionality?
Engineering
1 answer:
stepladder [879]3 years ago
5 0

Answer:

0.4 gallons per second

Explanation:

A function shows the relationship between an independent variable and a dependent variable.

The independent variable (x values) are input variables i.e. they don't depend on other variables while the dependent variable (y values) are output variables i.e. they depend on other variables.

The rate of change or slope or constant of proportionality is the ratio of the dependent variable (y value) to the independent variable (x value).

Given that the garden hose fills a 2-gallon bucket in 5 seconds. The dependent variable = g = number of gallons, the independent variable = t = number of seconds.

Constant of proportionality = g / t = 2 / 5 = 0.4 gallons per second

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g Calculate a better value for the convection coefficient using resources from heat transfer. Assume forced convection of the ai
ollegr [7]

Answer:results for h should on the same order of magnitude of the value I provided. If it isn't, check your units. Update to you calculated values for h and resolve your model.

Explanation:

4 0
3 years ago
Knowing that v = –8 m/s when t = 0 and v = 8 m/s when t = 2 s, determine the constant k. (Round the final answer to the nearest
docker41 [41]

Answer:

a)We know that acceleration a=dv/dt

So dv/dt=kt^2

dv=kt^2dt

Integrating we get

v(t)=kt^3/3+C

Puttin t=0

-8=C

Putting t=2

8=8k/3-8

k=48/8

k=6

5 0
3 years ago
An insulated rigid tank is initially evacuated. A valve is opened, and atmospheric air at 95 kPa and 17 ºC enters the tank until
Darya [45]

Answer:

T2= 406k

Explanation:

The temperature can be defined as the measurement of the intensity of the heat present in the object. Fahrenheit, kelvin and centigrade are the common scale used for measuring Temperature.

Given:

T1=170C

To convert to Kelvin

= 17+273 =290K

T1 = 290K

Pressure (P)= 95KPa

Specific heat ratio = CP/CV= K

WhereK=1.005/0.718

K = 1.4

The final temperature can be calculated using the formula below.

T2 = CP/CV × T1

=. K × T1

T2 = 1.4 × 290

T2= 406k

5 0
3 years ago
Mary is interested in developing new machines that would increase the productivity of small scale farmers. After high school, wh
vovangra [49]

Answer:

Agricultural engineering

Explanation:

Hello,

First, this area of engineering deals with design, construction and upgrade of farm equipment and machines for purpose of production and processing.

This course will equip Mary with the skills and knowledge that can be applied is solving challenges in the field of Agriculture especially in areas of power supplies, machinery efficiency, agricultural products storage and processing, environmental issues, pollution in the ecosystem and structures and facilities that improve agriculture.

The vital skills that Mary should develop while pursing this course are analytical skills to solve complicated systems, technical skills to do proper math, critical thinking skills to be able to think outside the box for solutions and communication skills to proper work with others.

Mary will learn about using software to design systems, machine operation and farm equipment.Her studies will cover ways of modifying the environment for sustainable agricultural practices.She will be able to know ways of testing farm equipment to ensure proper functionality and high output.This is a multi-disciplinary career, hence she will interact with civil engineers, contractors, environmentalists and other stakeholders to ensure the goals of projects are attained.

Hope this Helps Engineer!

8 0
3 years ago
For this homework you are writing a main function, with 3 subfunctions. 2. The "main" function is to be named arm_prop a. Inputs
ra1l [238]

Answer:

MATLAB CODE:

clc;

clear all;

x=[1 2 3 4]; %Input vector of variable size

[gm,ra,hm]=arm_prop(x) %Main function calling , output values are hm, ra, hm and imput is x

%% Main function

function [gm,ra,hm]=arm_prop(x)

[gm]=geo_mean(x); %Calling Sub function 1

[ra]=rms_avg(x); %Calling Sub function 2

[hm]=har_mean(x); %Calling Sub function 3

 

%Sub function 2 =Rms average

function [gm]=geo_mean(x)    

n=numel(x); %calculating number of elemnts in vector x

temp=1; %Temporary value for multiplying each and every value of x

for i=1:1:n % For loop run for number of elements in x

temp=temp*x(i); %Multliplyng each and every element of x

end

gm=temp^(1/n); % Calculating geometric mean

end

%Sub function 2 =Rms average

function [ra]=rms_avg(x)

temp=0; %Temporary value for adding square of each and every value of x

N=numel(x); %calculating number of elemnts in vector x

for i=1:1:N % For loop run for number of elements in x

temp=temp+x(i)^2; %Adding square of each and every element of x

end

ra=(temp/N)^(1/2); % Calculating Rms average

end

%Sub function 3 =Harmonic mean

function [hm]=har_mean(x)

temp=0; %Temporary value for adding reciprocal of each and every value of x

N=numel(x); %calculating number of elemnts in vector x

for i=1:1:N % For loop run for number of elements in x

temp=temp+(1/x(i)); %Adding sreciprocal of each and every element of x

end

hm=N/temp; % Halculating Harmonic mean

end

end

Results:

gm =

2.2134

ra =

2.7386

hm =

1.9200

Here in one main function. 3 sub functions are written. Every sub function returns one output. As all 3 sub functions are inside main function, main function returns 3 output values gm, ra, hm.

Explanation:

3 0
4 years ago
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