A rigid tank contains 5 kg of saturated vapor steam at 100°C. The steam is cooled to the ambient temperature of 25°C. (a) Sketch
the process with respect to the saturation lines on a T-vdiagram. Indicatepressure valuesat each state. (5pt) (b) Determinethe entropy change of the steam, in kJ/K. (10 pt) (c) Determinethe totalentropy change associated with this process, in kJ/K. (15pt)
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Answer:
the endurance strength = 421.24 MPa
Explanation:
From the given information; The objective is to estimate the endurance strength, Se, in MPa .
To do that; let's for see the expression that shows the relationship between the ultimate tensile strength and Brinell hardness number .
It is expressed as:
where;
= Brinell hardness number
= Ultimate tensile strength
From ;
; replace 290 for
; we have
988.9 MPa
We can see that the derived value for the ultimate tensile strength when the Brinell harness number = 290 is less than 1400 MPa ( i.e it is 988.9 MPa)
So; we can say
The Endurance limit can be represented by the formula:
= 494.45 MPa
Using Table 6.2 for parameter for Marin Surface modification factor. The value for a and b are derived; which are :
a = 1.58
b = -0.085
The value of the surface factor can be calculate by using the equation
The formula that is used to determine the value of for the rotating shaft of size factor d = 10 mm is as follows:
Finally; the the endurance strength, Se, in MPa if the rod is used in rotating bending is determined by using the expression;
= 0.8792×0.969×494.45
= 421.24 MPa
Thus; the endurance strength = 421.24 MPa