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Nastasia [14]
3 years ago
5

The outer surface temperature of a glass filled with iced water may drop below the dew-point temperature of the surrounding air,

causing the moisture in the vicinity of the glass to condense. After a while, the condensate may start dripping down because of gravity.
1. True
2. False
Engineering
1 answer:
user100 [1]3 years ago
3 0

Answer: True

Explanation:

The outer surface temperature of a glass filled with iced water will drop below dew-point temperature of the surrounding air, thereby resulting into the moisture in the vicinity of the glass to condense.

After some time, the condensate may start dripping down because of gravity. This is due to the fact that water will start condensing on glass surface below due point temperature. The adhesion force that water has with glass is low.

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An automobile having a mass of 1100 kg initially moves along a level highway at 110 km/h relative to the highway. It then climbs
Greeley [361]

Answer:

Change in kinetic energy=-513.652 KJ

Change in potential energy=431.64KJ

Explanation:

We are given that

Mass of an automobile , m=1100 kg

Initial speed, u=110 km/h=110\times \frac{5}{18}=30.56 m/s

Where 1 km/h=5/18 m/s

Height , h_2=40 m

g=9.81 m/s^2

Final speed, v=0

Change in kinetic energy,\Delta K.E=\frac{1}{2}m(v^2-u^2)

\Delta K.E=\frac{1}{2}(1100)(0-(30.56)^2)=-513652.48 J

\Delta K.E=-\frac{513652.48}{1000}=-513.652 KJ

Where 1 KJ=1000 J

Change in potential energy,\Delta P.E=mgh(h_2-h_1)

Initially height, h1=0

Using the formula

\Delta P.E=1100\times 9.81(40-0)

\Delta P.E=431640J

\Delta P.E=431.64KJ

6 0
3 years ago
What is a magnitute?
ValentinkaMS [17]

Answer:

Magnitude is a specific type of norm. Magnitude is what is known as the Euclidean norm. There are other norms, such as the Leibniz and the Chebychev norm.

Explanation:

5 0
3 years ago
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Chemical milling is used in an aircraft plant to create pockets in wing sections made of an aluminum alloy. The starting thickne
Lelu [443]

Answer:

a) metal removal rate is 1915.37 mm³/min

b) the time required to etch to the specified depth is 500 min or 8.333 hrs

Explanation:

Given the data in the question;

starting thickness of one work part of interest = 20 mm

depth of series of rectangular-shaped pockets = 12 mm

dimension of pocket = 200 mm by 400 mm

radius of corners of each rectangle = 15 mm

penetration rate = 0.024 mm/minute

etch factor = 1.75

a)

To get the metal removal rate MRR;

The initial area will be smaller compare to the given dimensions of 200mm by 400mm and the metal removal rate would increase during the cut as area is increased. so'

A = 200 × 400 - ( 30 × 30 - ( π × 15² ) )

= 80000 - ( 900 - 707 )      

= 80000 - 193

A = 79807 mm²

Hence, metal removal rate MRR = penetration rate × A

MRR = 0.024 mm/minute × 79807 mm²

MRR = 1915.37 mm³/min

Therefore, metal removal rate is 1915.37 mm³/min

b) To get the time required to etch to the specified depth;

Time to machine ( etch ) =  depth of series of rectangular-shaped pockets / penetration rate

we substitute

Time to machine ( etch ) = 12 mm / 0.024 mm/minute

Time to machine ( etch ) = 500 min or 8.333 hrs

Therefore, the time required to etch to the specified depth is 500 min or 8.333 hrs

3 0
3 years ago
3. (9 points) A square-thread power screw is used to raise or lower the basketball board in a gym, the weight of which is W = 10
Bezzdna [24]

Answer:

a) 49.95 watts

b) The self locking condition is satisfied

Explanation:

Given data

weight of the square-thread power screw ( w ) = 100 kg = 1000 N

diameter (d) = 20 mm ,

pitch (p) = 2 mm

friction coefficient of steel parts ( f ) = 0.1

Gravity constant ( g ) = 10 N/kg

Rotation of electric power screwdrivers = 300 rpm

A ) Determine the power needed to raise to the basket board

first we have to calculate T

T = Wtan (∝ + Ф ) * \frac{Dm}{2} ------------- equation 1

Dm = d - 0.5 ( 2) = 19mm

Tan ∝ = \frac{L}{\pi  Dm}  where L = 2*2 = 4

hence ∝ = 3.83⁰

given f = 0.1 , Tan Ф = 0.1.     hence Ф = 5.71⁰

insert all the values into equation 1

T = 1.59 Nm

Determine the power needed using this equation

\frac{2\pi NT }{60}   =  \frac{2\pi * 300 * 1.59}{60}

= 49.95 watts

B) checking if the self-locking condition of the power screw is satisfied

Ф > ∝  hence it is self locking condition is satisfied

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Which situation might cause potential hazards at a construction site?
nata0808 [166]

Answer:

D. protruding steel rebars .. #answerwithquality #BAL

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