Answer:
The entity relationship (ER) data model has existed for over 35 years. It is well suited to data modelling for use with databases because it is fairly abstract and is easy to discuss and explain. ER models are readily translated to relations. ER models, also called an ER schema, are represented by ER diagrams.
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
Based on the calculations, the magnitude (a) of it's total acceleration is equal to 2.71 m/s².
<u>Given the following data:</u>
- Angle of inclination = 10°.
- Radius of curvature, r = 40 meters.
- Acceleration of the minivan, A = 1.8 m/s².
- Initial velocity, u = 0 m/s (since it's starting from rest).
<h3>How to determine the magnitude (a) of it's total acceleration?</h3>
First of all, we would determine the final velocity of the minivan by applying the first equation of motion as follows:
V = u + at
V = 0 + 1.8 × 5
V = 9 m/s.
Next, we would calculate the centripetal acceleration of this minivan:
Ac = V²/r
Ac = 9²/40
Ac = 2.025 m/s².
Now, we can determine the magnitude (a) of it's total acceleration:
a = √(Ac² + A²)
a = √(2.025² + 1.8²)
a = 2.71 m/s².
Read more on acceleration here: brainly.com/question/24728358
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Answer:
The bending stress is 502.22 MPa
Explanation:
The diameter of the pinion is equal to:
Where
m = module = 5
Np = number of teeth of pinion = 26
= 0.13 m
The pitch line velocity is equal to:
Where
wp = speed of the pinion = 1800 rpm
The factor B is equal to:
The factor A is equal to:
A = 50 + 56*(1 - B) = 50 + 56*(1-0.396) = 83.82
The dynamic factor is:
The geometry bending factor at 20°, the application factor Ka, load distribution factor Km, the size factor Ks, the rim thickness factor Kb and Ki the idler factor can be obtained from tables
JR = 0.41
Ka = 1
Kb = 1
Ks = 1
Ki = 1.42
Km = 1.7
The diametrical pitch is equal to:
The bending stress is equal to:
