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pickupchik [31]
1 year ago
12

A formal indication from a state, on letterhead, or an official state form, that shows the applicant has valid driving privilege

s and is clear to apply for a colorado driver's license is called what?
Engineering
1 answer:
alex41 [277]1 year ago
7 0

A formal indication from a state, on letterhead, or an official state form, which shows that an applicant has valid driving privileges and is clear to apply for a Colorado driver's license is called a clearance.

<h3>What is a learner's license?</h3>

A learner's license is also referred to as learner's permit and it can be defined as a category of driver's license that is issued to an individual who is learning how to drive an automobile vehicle (car).

<h3>What is a license?</h3>

A license is also referred to as a certificate and it can be defined as an authorization that is typically issued by state governments to a driver, so as to avail him or her the legal ability to physically driver in all the states across a country.

In this scenario, we can infer and logically deduce that a clearance is a formal indication from a state which shows and affirms that an applicant has valid driving privileges, and is permitted to apply for a Colorado driver's license.

Learn more about learner's license here: brainly.com/question/26289148

#SPJ1

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no

Explanation:

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Which of the following should you avoid when pulling over to the curb?
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Explanation:

When preparing to move to a curb or side of the road you should always accelerate quickly to move ahead of traffic.

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Can the MOXIE created by NASA be used on earth
Alisiya [41]

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3 years ago
The cubic capacity of a four-stroke over-square spark-ignition engine is 245cc. The over-square ratio is (1.1) The clearance vol
pashok25 [27]

Answer:

Bore = 7 cm

stroke = 6.36 cm

compression ratio = 10.007

Explanation:

Given data:

Cubic capacity of the engine, V = 245 cc

Clearance volume, v = 27.2 cc

over square-ratio = 1.1

thus,

D/L = 1.1

where,

D is the bore

L is the stroke

Now,

V = \frac{\pi}{4}D^2L

or

V = \frac{\pi}{4}\frac{D^3}{1.1}

on substituting the values, we have

245 =  \frac{\pi}{4}\frac{D^3}{1.1}

or

D = 7.00 cm

Now,

we have

D/L = 1.1

thus,

L = D/1.1

L = 7/1.1

or

L= 6.36 cm

Now,

the compression ratio is given as:

\textup{compression ratio}=\frac{V+v}{v}

on substituting the values, we get

\textup{compression ratio}=\frac{245+27.2}{27.2}

or

Compression ratio = 10.007

4 0
3 years ago
The total solids production rate in an activated sludge aeration tank is 7240 kg/d on a dry mass basis. It is necessary to maint
snow_lady [41]

Answer:

volume of biological sludge = 28.566 m³ per day

Explanation:

given data

mass of solid = 7240 kg/day

initial moisture content = 78%

solution

here percentage of solid will be

% of solid = 100 - initial moisture content

% of solid = 100 - 78 = 22 %

so that

mass of sludge produced = \frac{100}{100 - P} M kg  per day

put her value

mass of sludge produced = \frac{100}{100 - 78} 7240 kg

mass of sludge produced = 32909.09 kg

so

specific gravity of sludge =  \frac{\rho sludge}{\rho water }

and as we know that

\frac{100}{S sludge} = \frac{solid percentage}{S solid} = \frac{water percentage}{S water}

\frac{100}{S sludge} = \frac{22}{2.5} = \frac{78}{1}

S sludge = 1.152

so that

density of sludge = S sludge × density of water

density of sludge = 1.152 × 1000

density of sludge = 1152 kg/m³

so that

volume of biological sludge = \frac{mass sludge produce}{\rho sludge}

volume of biological sludge = \frac{32909.09}{1152}

volume of biological sludge = 28.566 m³ per day

6 0
3 years ago
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