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Nutka1998 [239]
2 years ago
8

Help please :< I just need the answer for this as quickly as possible.

Chemistry
2 answers:
11Alexandr11 [23.1K]2 years ago
8 0

Answer:

I think its the 3th one

Explanation:

Anni [7]2 years ago
8 0
It’s the 3rd one or as you can say C
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Explain the law of conservation of energy.
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HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
Referring to an activity series, which of the following combinations of reactants would not produce a successful single-replacem
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Predict whether each of the following molecules is polar or non-polar:a) IF,b) CS2, c) SO3, d) PCl3, e) SF6, f) IF5.
BlackZzzverrR [31]
<h3><u>Answer;</u></h3>

Polar: IF, PCl3, IF5  

Nonpolar: CS2, SO3, SF6

<h3><u>Explanation:</u></h3>
  • Polar molecules form when two atoms do not share electrons equally in a covalent bond.
  • A molecule is classified as a polar molecule when the arrangement of the atoms is such that one end of the molecule has a positive electrical charge and the other end has a negative charge.
  • A non-polar molecule does not have electrical poles.The electrons are distributed more equally.
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