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musickatia [10]
3 years ago
15

Please Solve The Question! 10 Points!

Chemistry
2 answers:
frez [133]3 years ago
7 0

Answer:

AHHHHHHHHHHHHHH

Explanation:

sorry i need points

wariber [46]3 years ago
5 0
The first one is the 2Hg+.....
The second is the Ca+ 2H2O....
The third is the first one, H2 + Cl2...
And the last is Fe+ S= FeS
It was so easy
Good Luck
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Calculate ΔH° = for the chemical reaction
babymother [125]

Answer: \Delta H^0 for the reaction Cl_2(g)+F_2(g)\rightarrow 2ClF(g)  is -108kJ

Explanation:

The balanced chemical reaction is,

The expression for enthalpy change is,

\Delta H=[n\times B.E_{reactants}]-[n\times B.E{products}]

where, n = number of moles

Now put all the given values in this expression, we get

\Delta H=[1\times B.E_{Cl_2}+1\times B.E_{F_2}]-[2\times B.E_{ClF}]

\Delta H=[(1\times 243)+(1\times 159)]-[2\times 255]

\Delta H=-108kJ

Thus \Delta H^0 for the reaction Cl_2(g)+F_2(g)\rightarrow 2ClF(g)  is -108kJ

4 0
3 years ago
How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
poizon [28]

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>

5 0
4 years ago
(PLZ ANSWER SOON)
almond37 [142]

Answer:

10.5 k.J.

Explanation:

7 0
3 years ago
What is emission spectrum and absorption spectrum? ​
andrew-mc [135]
- emission spectrum is the amount of electromagnetic radiation of each frequency it emits when it is heated (or more generally when it is excited). When the electrons in the element are excited, they jump to higher energy levels.



- Absorption spectrum is a technique used to find out what makes up a sample of a substance – in other words, a chemical analysis.
4 0
2 years ago
Read 2 more answers
'Suppose you take 0.0332 kg of ammonium carbonate and dissolve it using 0.0395 kg of water. What would be the mass percent conce
VMariaS [17]

The solution is 45.7 % (NH₄)₂CO₃ by mass.

Mass of solution = 0.0332 kg + 0.0395 kg = 0.0727 kg

% (NH₄)₂CO₃ = Mass of (NH₄)₂CO₃/Total mass × 100 % = 0.0332 kg/0.0727 kg × 100 % = 45.7 %


8 0
4 years ago
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