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3 years ago

Akayo claims that there are centers of dialstiond through ehich a dialation of line n by a factor of 1.5 leaves line n unchanged

Mathematics

1 answer:

mars1129 [50]3 years ago

5 0

Answer:

See Explanation

Step-by-step explanation:

This question requires further details. In absence of the details, I will answer on a general term.

When a line is dilated (whether expanded or compressed), the new line will be on the same line with the dilated line; however, the length of both lines will be different

Take for instance:

Line AB of coordinate (1,3) is horizontally dilated by 2,

Horizontal dilation rule is: y = f(cx) where c is the dilation factor

So, the new point will be

A'B' = (1, 3 * 2)

A'B' = (1,6)

When you compare the x coordinate of both line, you will observe that they have the same x coordinate of 1.

This implies that they are on the same level but different length

The same is applicable to vertical dilation

the new point will be:

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Por favor necesito ayuda

IgorC [24]

Answer: Ingasu, yo tambien no se guey.

Step-by-step explanation: Nomas ponle 35°

3 0

3 years ago

What is the solution to the following system?

leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

$\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]$

Now I will shift rows to make my pivot point (top left) a 1 and so:

$\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]$

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

$\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]$

$\frac{R_2}{9}=R_2$

$\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]$

4R2+R1=R1 , -14R2+R3=R3

$\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]$

$-\frac{9}{20}R_3=R_3$

$\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]$

$-\frac{4}{9}R_3+R_2=R2$ , $-\frac{7}{9}R_3+R_1=R_1$

$\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]$

Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to". Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0

3 years ago

Find the nth term 1, 5, 9. 13, 17

mojhsa [17]

a1 = 1 and d = 4

a(n) = a1 + d(n - 1)

a(n) = 1 + 4(n - 1)

8 0

3 years ago

Can someone please help me with these

OLga [1]

Answer:

1. 1072.6

2. 753.6

3. 194.2

4. 59.5

5. 4848.3

6. 1818.3

Step-by-step explanation:

We have to use the trigonometric functions sin, cos, and tan. Remember the mnemonic SOH-CAH-TOA when solving these problems. (sinθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse, tanθ=opposite/adjacent)

1. tan(40)=900/x

x=900/tan(40)

x=1072.6

2. tan(37)=x/1000

1000tan(37)=x

753.6=x

3. sin(18)=60/x

x=60/sin(18)

x=194.2

4. sin(48)=x/80

80sin(48)=x

59.5=x

5. tan(22)=x/12000

12000tan(22)=x

4848.3=x

6. tan(33)=x/2800

2800tan(33)=x

1818.3=x

7 0

3 years ago

The price for strawberries is currently $ 6.40 per pack. next week,strawberries will be on sale at a 20% discount. what is the t

notka56 [123]

Answer:

answer is $5.12

Step-by-step explanation:

Using the formula two and replacing the given values:

Sale Price = Original Price - Amount Saved. So,

Sale Price = 6.40 - 1.28

Sale Price = $5.12 (answer)

This means, the cost of the item to you is $5.12.

You will pay $5.12 for an item with original price of $6.40 when discounted 20%. In other words, if you buy an item at $6.40 with 20% discounts, you pay $6.40 - 1.28 = $5.12

Suppose Have you received a amazon promo code of 1.28. If the price is $6.40 what was the amount saved in percent:

3) 1.28 is what percent off $6.40?

Using the formula two and replacing the given values:

Amount Saved = Original Price x Discount % /100. So,

1.28 = 6.40 x Discount % / 100

1.28 / 6.40 = Discount % /100

100 x 1.28 / 6.40 = Discount %

128 / 6.40 = Discount %, or

Discount % = 20 (answer)

8 0

4 years ago