Answer is: <span>C. propanal. 1-propanol is primary alcohol. With weak oxidizing agent primary alcohol gives aldehyde and with strong oxidizing agent primary alcohol gives carbonic acid. </span>Oxidation of 1-propanol with <span>Na</span>₂<span>Cr</span>₂<span>O</span>₇<span> and sulfuric acid</span><span> gives propanal and o</span><span>xidation with </span>chromic acid<span> gives </span>propionic acid<span>.</span>
Organic compounds have different functional groups. It is possible to convert from one functional group to another by using proper oxidizing and reducing agents.
Alcohols are oxidized to aldehydes . Here porpanal is the aldehyde and propanol is the alcohol.
We see from the reaction side of the equation that we have 2 Li. That means we need the same number of Li on the products side. Therefore, our only option is 2.
