Answer:
87.5 mi/hr
Explanation:
Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.
vf = 60 mi/hr
vi = 0 mi/hr
Δt = 8 secs
a = vf - vi/ Δt
= 60 mi/hr - 0 mi/hr/ 8 secs
= 60 mi/hr / 8 secs
= 7.5 mi/hr^2
Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.
vi = 50 mi/ hr
Δt = 5 secs
a = 7.5 mi/ hr^2
a = vf - vi/ Δt
7.5 = vf - 50 mi/hr / 5 secs
37.5 = vf - 50
87.5 mi/ hr = vf
Answer:
The answer is c
Explanation:
Because all of the Other ones did not make sense
Answer:
2–butyne.
Explanation:
To name the compound given above, we must determine the following:
1. Determine the functional group of the compound.
2. Determine the longest continuous carbon chain. This gives the parent name of the compound.
3. Locate the position of the functional group by giving it the lowest possible count.
4. Combine the above to obtain the name.
Thus, we shall name the compound as follow:
1. The compound contains triple bond (C≡C). Therefore, the compound is an alkyne.
2. The longest chain is carbon 4. Thus the parent is butyne.
3. The triple bond (C≡C) is located at carbon 2 when we count from either side.
4. The name of the compound is:
2–butyne
