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Alenkasestr [34]
2 years ago
12

The densities of various substances are listed in the chart. All of these substances have the same

Chemistry
1 answer:
Butoxors [25]2 years ago
6 0

Answer:

The object with the greatest density

Explanation:

The object that will have the greatest mass from the given choices is the one with greatest density.

Density is the mass per unit volume of a substance;

  Density = \frac{mass}{volume}  

We can see that density is directly proportional to the mass and inversely proportional to the volume.

The more the mass and the lesser the volume, the higher the density.

So, since the volume is the same, and mass is directly proportional to density, the object having the highest density will have the greatest mass.

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Acetone (nail polish remover) has a density of 0.7857 g >cm3.
Stella [2.4K]

If acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

<h3>What is acetone?</h3>

Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.

Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.

In the statement we can find that acetone has a density of 0.7857 \frac{g}{cm^{3} }.

Therefore, we can confirm that if acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

To learn more about acetone visit: brainly.com/question/13334667?referrer=searchResults

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7 0
2 years ago
Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000
olga55 [171]
The answer is D! 512000000
5 0
3 years ago
Read 2 more answers
During a lab experiment, students are supposed to add small pieces of magnesium, aluminum, and calcium metal to concentrated hyd
ser-zykov [4K]
Hydrogen gas is highly flammable.
5 0
3 years ago
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Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq
Ilia_Sergeevich [38]

Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                   

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

7 0
3 years ago
You used a calorimeter in the heat transfer lab. Explain how the calorimeter works, and how to calculate the heat given off or a
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Q = mcΔT 
To find the heat released.
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