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liraira [26]
3 years ago
7

In this lab, you will use the flame test to identify the metal ion in two boxes of unidentified fireworks. Write an investigativ

e question that you can answer by doing this experiment.
Chemistry
2 answers:
Rasek [7]3 years ago
6 0
In a flame photometric analysis, salt solution is first vaporized using the heat of flame, followed by this electrons from valance shell gets excited from ground state to excited state. Followed by this de-excitation of electron bring backs electrons to ground state. This process is accompanied by emission of photon. The photon emitted is characteristic of an element, and number of photons emitted can be used for quantitative analysis. 

<span>Following are the investigative question that you can answer by doing this experiment.
</span>1) What information can be obtained from the colour of flame?
2) <span>State the relationship between wavelength, frequency, and energy?
</span><span>3) Can you identify the metal present in unknown sample provided?
4) How will you identify amount of metal present in sample solution?
5) </span><span>Why do different chemicals emit light of different colour?</span><span>

</span>
valentina_108 [34]3 years ago
6 0

The first one is chlorine ion, the second one is metal ion.

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What distinguishes compounds from mixtures?
dexar [7]

Answer:

There's a very small difference between the two...a compound is when you mix several elements to create a whole new one. A mixture is when you mix several elements together, but instead of it creating a completely different compound, it's simply just a few elements mixed together.

3 0
3 years ago
HELP PLLZZZ
Scorpion4ik [409]

Answer:

Abrasion

Explanation:

Here's an example, strong winds on a beach where some rocks are cause the sand to rub against the rocks, causing heat and eventually crack and destroy the rock. The ice of glaciers can also break down rocks when rocks are frozen inside it, and that's cooling.

8 0
3 years ago
Read 2 more answers
Hydrochloric acid (HCl) and sodium hydroxide (NaOH) react to form water and sodium chloride (NaCl). If you have 2.87 g of HCl, 3
wlad13 [49]

Answer:

2.86g

Explanation:

Mass of HCl  = 2.87g

Mass of water  = 3.75g

Mass of NaCl  = 1.98g

Unknown:

Mass of NaOH reacted  = ?

Solution:

  The reaction expression is given as:

           HCl    +   NaOH   →   NaCl   +  H₂O

According to the law of conservation of mass, the mass of reactants and products must be the same.

   Mass of HCl   +   Mass of NaOH  = Mass of NaCl  +  Mass of H₂O

      2.87g + Mass of NaOH  = 1.98g + 3.75g

           Mass of NaOH  = 1.98g + 3.75g - 2.87g  = 2.86g

7 0
3 years ago
The wavelength idea of the wave-mechanical model refers to what?
Virty [35]
<span> The wave idea derives from the electrons' behavior about the nucleus of an atom, and it follows Heisenberg's Uncertainty Principle and draws away from Bohr's planetary model of the atom.</span>
6 0
3 years ago
Calculate the percentage yield for the reaction represented by the equation CH4 + 2O2 ? 2H2O + CO2 when 1000 g of CH2 react with
makvit [3.9K]

Answer:

83.64%.

Explanation:

∵ The percent yield = (actual yield/theoretical yield)*100.

actual yield of CO₂ = 2300 g.

  • We need to find the theoretical yield of CO₂:

For the reaction:

<em>CH₄ + 2O₂ → 2H₂O + CO₂,</em>

1.0 mol of CH₄ react with 2 mol of O₂ to produce 2 mol of H₂O and 1.0 mol of CO₂.

  • Firstly, we need to calculate the no. of moles of 1000 g of CH₄ using the relation:

<em>no. of moles of CH₄ = mass/molar mass</em> = (1000 g)/(16.0 g/mol) = <em>62.5 mol.</em>

<u><em>Using cross-multiplication:</em></u>

1.0 mol of CH₄ produces → 1.0 mol of CO₂, from stichiometry.

∴ 62.5 mol of CH₄ produces → 62.5 mol of CO₂.

  • We can calculate the theoretical yield of carbon dioxide gas using the relation:

∴ The theoretical yield of CO₂ gas = n*molar mass = (62.5 mol)(44.0 g/mol) = 2750 g.

<em>∵ The percent yield = (actual yield/theoretical yield)*100.</em>

actual yield = 2300 g, theoretical yield = 2750 g.

<em>∴ the percent yield</em> = (2300 g/2750 g)*100 = <em>83.64%.</em>

5 0
3 years ago
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