In this lab, you will use the flame test to identify the metal ion in two boxes of unidentified fireworks. Write an investigativ
2 answers:
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The force of attraction that results in holding of atoms or ions together in a molecule or crystal is said be bonding. Bond formation can take place by either attraction or transfer of electrons. There are single, double, and triple bonds. There are many types of bonding namely:
Covalent (sharing of electrons takes place).
Ionic (transfer of electrons takes place).
Metallic (ionized atoms of metals and the sea of electrons around them).
- Brass (a copper-zinc alloy)
Brass is an alloy of metal that is copper and zinc. Hence, the metallic bonding is present in the brass.
- Rubber
It is a polymer whose monomer unit is isoprene, which is a covalent compound. The isoprene units are attached in repeated units to form rubber by covalent bonding.
- Barium sulfide (
)
Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.
- Solid xenon
Only xenon atoms are present in solid xenon which are interacted by weak Van der Waal's interactions.
- Bronze
Bronze is an alloy of metal that is copper and tin. Hence, the metallic bonding is present in the brass.
- Nylon
It is a polymer whose monomer unit is caprolactam, which is a covalent compound. The caprolactam units are attached in repeated units to form nylon by covalent bonding.
- Aluminum phosphide (
)
Aluminum phosphide is a covalent compound and thus involves covalent bonding.
Please, find the complete question in the picture attached.
Answer:
1. Na₂O
2. AlF₃
3. MgO
4. Ca₃P₂
Explanation:
1. Na⁺ and O²⁻
An ionic compound will be formed when two ions of opposite charge attract each other.
The positive ion is called cation and the negative ion is called anion.
Thus, every ionic compound has a cation and an anion electrostatically bonded.
The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.
This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.
Simbolically:
As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.
Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:
- Na₂O
2. Al³⁺ and F⁻
- The subscript of Al will be 1 (because the F ion has charge 1-, and the subscript of F will be 3 (because the Al ion has charge +3).
Thus the ionic compound formed by this pair of ions is:
- AlF₃
3. Mg²⁺ and S²⁻
- The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:
That results in the formula: Mg₂S₂
Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:
- MgO
4. Ca²⁺ and P³⁻
- The charge 2+ from Ca will become subscript 2 for P and the charge 3- whill become subscript 3 for Ca.
Hence, the ionic compound formed by these two ions is:
- Ca₃P₂
