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Mice21 [21]
2 years ago
7

Ms. Howard's science class looked at the group of stars called the Big Dipper, They watched it in the early evening during fall

and spring. This is what
they saw:
Fall- upright and low in the sky
Spring - upside down and high in sky
Why does the position of the Big Dipper change during the year?
O A Earth revolves around the Sun,
OB. The position of the Moon is different in the fall than in the spring.
O C. The Big Dipper is made of different stars in the fall than in the spring.
OD. The Big Dipper moves toward Earth in the fall and away in the spring.

Physics
1 answer:
poizon [28]2 years ago
7 0
I would say c is the correct answer
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If 8.65 g of a tin - fluorine compound contains 5.28 g of tin, what is its empirical formula?
allsm [11]
First, we need to know the amounts of the elements in the compound.

Tin (Sn)= 5.28 g
Fluorine (F) = 8.65 - 5.28 = 3.37 g

Convert these to units of moles by dividing the molar masses.

Tin (Sn)= 5.28 g / 118.71 g/mol = 0.044 mol
Fluorine (F) = 3.37 g / 19.00 g/mol = 0.177 mol

Divide both by the least number of moles of the two.


Tin (Sn)= 0.044 mol /  0.044 mol = 1
Fluorine (F) =  0.177 mol / 0.044 mol = 4

Therefore, the empirical formula would be:
SnF4
4 0
3 years ago
Read 2 more answers
A rock is dropped from a distance RE above the surface of the earth, and is observed to have kinetic energy K1 when it hits the
goblinko [34]

Answer:

\dfrac{K_2}{K_1}=\dfrac{4}{3}

Explanation:

When an object strikes the ground, the potential energy of the rock gets converted to the kinetic energy.

A rock is dropped from a distance R_e above the surface of the earth and is observed to have kinetic energy K_1 when it hits the ground.

For another rock, It is dropped from twice the height 2R_e above the earth’s surface and has kinetic energy K_2 when it hits.              

For the first rock, K_1=GMm(\dfrac{1}{R_e}-\dfrac{1}{2R_e})=\dfrac{GMm}{2R_e}..............(1)

For the second rock, K_2=GMm(\dfrac{1}{R_e}-\dfrac{1}{3R_e})=\dfrac{2GMm}{3R_e}..............(2)

Dividing equation (2) by (1) we get :

\dfrac{K_2}{K_1}=\dfrac{4}{3}

Hence, this is the required solution.                                            

8 0
3 years ago
A 975-kg sports car (including driver) crosses the rounded top of a hill (radius = 88.0 m) at 18.0 m/s. Determine (a) the normal
Elan Coil [88]

Answer: a) 5965.2N b) 379.2N c) 29.37m/s

Explanation: shown in the attachment

6 0
3 years ago
A race car starts from rest on a circular track. The car increases its speed at a constant rate at as it goes 4.25 times around
miskamm [114]

Answer:

Angle = 1.07°

Explanation:

Total acceleration consists of translational acceleration (a) which is tangential and centripetal acceleration which is (radial).

Now, Tangential and radial acceleration are always perpendicular to each other. Thus, in a triangle system they are opposite and adjacent sides. From trigonometric ratios,

Opposite/Adjacent = tanθ

Now centripetal acceleration is given as v²/r

Thus, the angle to the radial is given as;

tanθ = translational acceleration/centripetal acceleration

So, tanθ = a/(v²/r) = ar/v²

Thus, θ = tan^(-1)(ar/v²)

Now, Distance of one round of circular motion of 'r' radius

= circumference of circle = 2πr

N = number of trips car makes around the circle

Thus,

total distance = 2πrN

Now, from equation of motion, we know that v² = u² + 2as

Where s is total distance and u is initial velocity which is zero in this case.

Thus, v² = 0² + 2as

Making s the subject;

s = v²/2a

Thus,

2πrN = v²/2a

So let's simplify to bring out ar/v² which is what we will use to calculate the angle. So,

2πrN x 2a = v²

4πN(ar) = v²

Thus, ar/v² = 1/(4πN)

From the question, N = 4.25

Thus,

ar/v² = 1/(4π x 4.25) = 0.0187

From earlier, we saw that the angle is given by;

θ = tan^(-1)(ar/v²)

Thus, θ = tan^(-1)(0.0187)

θ = 1.07°

6 0
3 years ago
A mixture that appears to contain only one substance is a(n)
bekas [8.4K]

Answer:

mixtures that appear to be the same throughout are homogenous mixtures

8 0
3 years ago
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