Answer:
The answer to your question is below
Explanation:
Data
light speed = 300 000 km/s
a) Express it in scientific notation
to do it, we just move the decimal point 5 places to the left
300 000 = 3.0 x 10 ⁵ km/s
b) Convert this value to meters per hour
(300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1
= 1.08 x 10¹² m/h
c) What distance in centimeters does light travel in 1 s?
data
v = 300 000 km/s
d = ?
t = 1 s
formula v = d/t we clear distance d = vxt
d = 300000 x 1 = 300000 km
d = 300000000 m = 30000000000 cm
7A 8A maybe I’m not sure sorry if it’s wrong.
For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
<h3>What is the e
lectric field intensity 20cm away from the
rod along its perpendicular
bisector?</h3>
Generally, the equation for the initial electric field intensity is mathematically given as
Therefore
Hence
E1=B*9*10^{13})/(10*110)*
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
Read more about Electric field
brainly.com/question/9383604
Answer:
Poke or kick the boxes. The sand box is the one that resists the most
Explanation:
The one that resists the most a change in motion (inertia) is the one with the greater mass—the one filled with sand. Since we cannot open the boxes or perform any weight measurement we can distinguish them by their inertia. Sand has greater mass and thus greater inertia
Answer:
Explanation:
a ) The volume of blood flowing per second throughout the vessel is constant .
a₁ v₁ = a₂ v₂
a₁ and a₂ are cross sectional area at two places of vessel and v₁ and v₂ are velocity of blood at these places .
2A x v₁ = A x .40
v₁ = .20 m /s
b )
Let normal pressure be P₁ when cross sectional area is 2A and at cross sectional area A , pressure is P₂
Applying Bernoulli's theorem
P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²
P₁ - P₂ = 1/2 ρ(v₂² - v₁² )
= .5 x 1060 ( .4² - .2² )
= 63.6 Pa .
