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3 years ago

What kind of waves can cause the most damage on the earth's surface?

Physics

2 answers:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

Surface waves, in contrast to body waves can only move along the surface. They arrive after the main P and S waves and are confined to the outer layers of the Earth. They cause the most surface destruction. Earthquake surface waves are divided into two different categories: Love and Rayleigh.

Explanation:

Hope this helped Mark BRAINLIEST!!!

kvasek [131]3 years ago

4 0

Answer:

Surface waves are the seismic waves that cause the most damage.

Explanation:

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A rope is shaken and produces 2 waves each second. Calculate the time period of the rope waves.

motikmotik

Answer:

0.5 s

Explanation:

From the question given above, the following data were obtained:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

Period of a wave is simply defined as the time taken to make one complete oscillation. Mathematically, it can be expressed as:

T = t / n

Whereb

T => is the period

t => is the space time

n => is the number of circle or oscillation.

With the above formula, we can obtain the period of the wave as follow:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

T = t / n

T = 1 / 2

T = 0.5 s

Thus, the period of the wave is 0.5 s

7 0

3 years ago

A filamentary conductor is formed into an equilateral triangle with sides of length carrying current i . find the magnetic field

arsen [322]

magnetic field due to a finite straight conductor is given by

$B = \frac{\mu_0 i}{4\pi r}(sin\theta_1 + sin\theta_2)$

here since it forms an equilateral triangle so we will have

$\theta_1 = \theta_2 = 60 degre$

also the perpendicular distance of the point from the wire is

$r = \frac{a}{2\sqrt3}$

now from the above equation magnetic field due to one wire is given by

$B = \frac{\mu_0 i}{4\pi \frac{a}{2\sqrt3}(sin60 + sin60)$

$B = \frac{\mu_0 i*2\sqrt3}{4\pi a}(\sqrt3)$

$B = \frac{3\mu_0 i}{2\pi a}$

now since in equilateral triangle there are three such wires so net magnetic field will be

$B = \frac{9\mu_0 i}{2\pi a}$

5 0

3 years ago

A jet is travelling at a speed of 1200 km/h and drops cargo from a height of 2.5 km above the ground Calculate the time it takes

OLEGan [10]

a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

$y(t) = h +u_y t - \frac{1}{2}gt^2$

where

h = 2.5 km = 2500 m is the initial height

$u_y = 0$ is the initial vertical velocity of the cargo

g = 9.8 m/s^2 is the acceleration of gravity

The cargo reaches the ground when

$y(t) = 0$

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

$0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s$

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

$v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s$

So the horizontal distance travelled is

$d=v_x t$

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

$d=(333.3)(22.6)=7533 m = 7.5 km$

7 0

3 years ago

HELP!

Angelina_Jolie [31]

Answer:

speed is increasing.

this is because the graph has a positive slope (due to it going up ), if it were decreasing, the graph would be going down

4 0

3 years ago

Read 2 more answers

Help with this question please.

mr Goodwill [35]

There are 4 hydrogens on the right side $(2\mathrm H_2=4\mathrm H)$ , and 2 hydrogens on the left per molecule of $\mathrm H_2$ . To get the same number of hydrogens on both sides, the coefficient should be 2.

(Then the number of oxygens will be consistent, since $2\mathrm H_2\mathrm O$ contributes 2 oxygens, and so does $\mathrm O_2$ .)

5 0

3 years ago