Answer:
The mass of
in the container is 2.074 gram
Explanation:
Given:
Volume of
lit
Equilibrium constant 
The reaction in which
is produced
⇄ 
Here equal moles of
and
is formed.
From the formula of equilibrium constant,


M
Above value shows,

So in 2 L no. moles of
=
moles.
So mass of 0.122 mole of
is =
g
Therefore, the mass of
in the container is 2.074 gram
Explanation:

Moles of compound =

We have ;
Volume of solution = 600 mL = 0.600 L ( 1 mL = 0.001 L)
Moles of NaOH = n
Molarity of the solution = 3 M

n = 3 M × 0.600 L = 1.800 mol
Mass of 1.800 mole sof NaOH :
1.800 mol × 40 g/mol = 72.0 g
Preparation:
Weight 72.0 grams of sodium hydroxide and add it to the 500 mL of volumetric flask along with some water. Dissolve the all the solute by adding small proportion of water. After the solution becomes clear make the water upto the mark of 500 ml.
Transfer the solution to a bigger beaker and 100 mL of water more to it.
The answer is 2H2 + O2----> 2H2O
<span>I believe an oxidation reaction is occurring</span>