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maxonik [38]
3 years ago
6

27. Apply the Pauli exclusion principle, the aufbau princi-

Chemistry
1 answer:
Slav-nsk [51]3 years ago
5 0

The Pauli exclusion principle and Hund's rule are important principles to follow when writing electron configuration or drawing orbital diagrams.

Hund's rule is applicable when filling degenerate orbitals. Electrons are first filled singly before they are paired in degenerate orbitals.

Pauli exclusion principle states that two electrons can not have the same value for all the four quantum numbers.

As such; the electron configuration of the elements are;

silicon: 1s2 2s2 2p6 3s2 3p2

fluorine: 1s2 2s2 2p5

calcium: 1s2 2s2 2p6 3s2 3p6 4s2

krypton: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

The orbital diagrams are shown in the images attached;

Image 1: Fluorine

Image 2: Silicon

Image 3: Calcium

Image 4: Krypton

Learn more: brainly.com/question/14283892

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What volume of a 6.67 M NaCl solution contains 3.12 mol NaCl? L
harkovskaia [24]

Answer:

0.47dm³

Explanation

Given parameters :

Molarity of NaCl = 6.67M

Number of moles = 3.12mol

Volume of NaCl =?

Volume of NaCl = number of moles/Molarity

Volume of NaCl = 3.12mol/6.67M

Volume of NaCl = 0.47dm³

4 0
3 years ago
Read 2 more answers
PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!!!
LuckyWell [14K]

Q.1-

Given,

mass - 10grams

volume - 24 cm³

density = mass/volume

density = 10/24

density = 0.416 g/cm³

Q.2-

Given,

mass - 700grams

volume - 1100cm³

density = mass/volume

density = 700/1100

density = 0.6363 g/cm³

5 0
3 years ago
Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

4 0
3 years ago
Molecular motion is a measure of the movement of the molecules in a substance. Molecular motion is substantially different betwe
Ainat [17]
The answer would be "air, wood". Gases have the highest Kinetic energy and least Potential energy. Liquids have the 2nd highest Kinetic energy and 2nd least potential energy and solids have the least kinetic energy and highest potential energy.
4 0
3 years ago
Read 2 more answers
A chemist has 3.55x1022 molecules of nitrogen monoxide. How
Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.55 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.05897...

We have the final answer as

<h3>0.059 moles</h3>

Hope this helps you

6 0
3 years ago
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