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3 years ago

Explain how fluorine and aluminum would exchange valence electrons to form an ionic compound.

Chemistry

2 answers:

Butoxors [25]3 years ago

6 0

Answer: through their valence electrons

Explanation: It is important to know first that the valence electrons are what is involved in bonding.

Fluorine is group 7(halogens) and have 7 electrons. All members of this groups have 7 valence electron each e.g Chlorine, Bromine, Iodine

Aluminum is in group 3 and has 3 valence electrons.

Elements bonds to attain the duplet (2 electron maximum) and octet (8 electron maximum) electronic configuration which is the stable state.

Fluorine requires one electron to attain the octet state while aluminum need to give out 3 electrons to attain the octet state.

So Aluminum will just give out the 3 electrons to 3 fluorine atoms. One electron to each of them and they will both be stable. Simplified below;

Al + 3F - AlF3

o-na [289]3 years ago

5 0

Answer :

Explanation :

The aluminium and fluorine react to give ionic compound aluminium fluoride.

Aluminium has 1 valence electrons in their shell and fluorine has 7 valence electrons in their shell.

For the complete octet, both aluminium and fluorine exchange valence electrons to form an ionic compound.

The aluminium donates its three valence electrons to three fluorine atoms and they form one $Al^{3+}$ and three $F^-$ ions.

Electron transfer image is shown below.

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jolli1 [7]

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According to the following position vs. Time graph the bicyclist was

julia-pushkina [17]

Answer:

According to the following position vs. Time graph the bicyclist was : D

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11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solut

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For the reactants,

The oxidation number of hydrogen = +1
The oxidation number of oxygen = -2
The oxidation number of arsenic = +5
The oxidation number of carbon = +3

For the products,

The oxidation number of hydrogen = +1
The oxidation number of oxygen = -2
The oxidation number of arsenic = +3
The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: $\text{H}_{3}\text{AsO}_{4}$

formula of the reducing agent: $\text{H}_{2}\text{C}_{2}\text{O}_{4}$

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2 years ago