Answer:
ρ = 4407.03 kg/m³
Explanation:
The Density of a metal alloy is given by the following equation:
1/ρ = m₁/ρ₁ + m₂/ρ₂ + m₃/ρ₃
where,
ρ = density of allow = ?
ρ₁ = density of Titanium (Ti) = 4540 kg/m³
ρ₂ = density of Aluminum (Al) = 2710 kg/m³
ρ₃ = density of Vanadium (V) = 6110 kg/m³
m₁ = mass fraction of Titanium (Ti) = 90% = 0.9
m₂ = mass fraction of Aluminum (Ti) = 6% = 0.06
m₁ = mass fraction of Vanadium (V) = 4% = 0.04
Therefore,
1/ρ = 0.9/(4540 kg/m³) + (0.06)/(2710 kg/m³) + (0.04)/(6110 kg/m³)
1/ρ = 1.9823 x 10⁺⁴ m³/kg + 0.2214 x 10⁻⁴ m³/kg + 0.0654 x 10⁻⁴ m³/kg
1/ρ = 2.2691 x 10⁻⁴ m³/kg
ρ = 1/(2.2691 x 10⁻⁴ m³/kg)
<u>ρ = 4407.03 kg/m³</u>
The volume that a 0.323-mol sample of a gas will occupy at 265 K and a pressure of 0.900 atm is 7.81L.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- R = gas law constant (0.0821 Latm/molK)
- n = number of moles
- T = temperature (K)
V = 0.323 × 0.0821 × 265 ÷ 0.900
V = 7.027 ÷ 0.9
V = 7.81L
Therefore, the volume that a 0.323-mol sample of a gas will occupy at 265 K and a pressure of 0.900 atm is 7.81L.
Learn more about volume at: brainly.com/question/1578538
Answer:
0.54 mole
Explanation:
CH3COOH CH3CH2OH CH3COOCH2CH3 H2O
Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol
Change - x - x + x + x
Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)
K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]
x*(1.0+x)/(1.0-x)(1.0-x) = 4.0
x+x²=4*(1-x)²
x+x² = 4(1² - 2x + x²)
x + x² = 4 - 8x + 4x²
4 - 8x + 4x²- x² - x= 0
3x² - 9x + 4 = 0
x=2.5 , x=0.54
2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,
so answer is 0.54 mole.
Thank you for posting your question here. I am just assuming to that the density of tin is <span>7.31 g/cm^3, you can change it it is not the number. Below is the solution. I hope it helps.
</span><span>95.04g x (1 cm³ / 7.31g) = 13.0 cm³</span>