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3 years ago

If 5 milliliters of a liquid has a mass of 10 grams what is the density of the liquid

1 answer:

4 0

So density = mass ÷ volume

∴ if mass of liquid = 10 g and volume = 5 ml

then density of liquid = 10 g ÷ 5 ml

= 2 g / ml

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How many moles of O2 are needed to burn 2.56 moles of CH3OH?

lukranit [14]

Answer:

$n_{O_2}=3.84molO_2$

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

$CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O$

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

$n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2$

Best regards!

6 0

2 years ago

Write down the formula for B<br> example:<br> Hydrogen + Fluorine = Hydrogen Fluorine <br><br> help

Tom [10]

Answer:

P³⁻ + Cl⁻ --> PCl₃

Explanation:

PCl₃: phosphorus trichloride. prefix in front of chloride is "tri"–meaning three.

5 0

3 years ago

Read 2 more answers

The bonds of four salts (MgBr2, NaCl, MgCl2, and NaBr) are evaluated for ionic character based on electronegativity differences

sammy [17]

Answer:

MgBr2 < MgCl2 < NaBr < NaCl

Explanation:

In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.

MgBr2 > ΔΕΝ = 1.8

NaCl > ΔΕΝ = 2.3

MgCl2 > ΔΕΝ = 2

NaBr > ΔΕΝ = 2.1

6 0

2 years ago

What is the end result of a nuclear fusion reaction?

julia-pushkina [17]

Answer:A.) molecule of atoms forms

Explanation:

7 0

3 years ago

Read 2 more answers

For the reaction of hydrogen with iodine

fenix001 [56]

Answer:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Explanation:

Hello!

In this case, considering the given chemical reaction:

$H_2(g) + I_2(g) \rightarrow 2HI(g)$

Thus, by applying the law of rate proportions, we can write:

$\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}$

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Best regards!

8 0

2 years ago