A cube with sides of area 32 cm2 contains a 35.9 nanoCoulomb charge. Find the flux of the electric field through the surface of
the cube in unis of Nm2/C.
1 answer:
Answer:
The electric flux through the surface is equal to 3.878 x 10³ Nm²/C
The field distance r is equal to half the length of each side of the cube.
From the area the length of each size was calculated and the field distance and charge were used in calculating the magnitude of the electric field vector which was found to be 202 x 10³ N/C
The total flux area available to this electric field is 6x32cm²
Explanation:
The full solution can be found in the attachment below.
Thank you for reading this post and I hope it is helpful to you.
You might be interested in
The y-component of the acceleration is
Explanation:
The y-component of the acceleration is given by:
where
is the y-component of the final velocity
is the y-component of the initial velocity
t is the time elapsed
For the ice skater in this problem, we have:
where
u = 2.25 m/s is the initial velocity
is the initial direction
, where
v = 4.65 m/s is the final velocity
is the final direction
The time elapsed is
t = 8.33 s
Therefore, we can find the y-component of the acceleration:
Learn more about acceleration:
#LearnwithBrainly