A cube with sides of area 32 cm2 contains a 35.9 nanoCoulomb charge. Find the flux of the electric field through the surface of
the cube in unis of Nm2/C.
1 answer:
Answer:
The electric flux through the surface is equal to 3.878 x 10³ Nm²/C
The field distance r is equal to half the length of each side of the cube.
From the area the length of each size was calculated and the field distance and charge were used in calculating the magnitude of the electric field vector which was found to be 202 x 10³ N/C
The total flux area available to this electric field is 6x32cm²
Explanation:
The full solution can be found in the attachment below.
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Answer:
Explanation:
Given:
The area of the house
The height of the house
We need to find the volume of a typical house.
Solution:
We find the volume of the house by multiplying the area of the house and height of the house.
Area and height of the house are known, so we substitute these value in above equation.
Now we convert the unit from feet to meter.
Divide the volume by 3.2808 for
Therefore, the volume of the house is