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3 years ago

What is true about the elements that make up a mineral?

Physics

1 answer:

Mashutka [201]3 years ago

3 0

Answer:

All minerals have a definite chemical makeup. ... For example, the mineral hematite has two iron atoms for every three oxygen atoms. The mineral magnetite has three iron atoms for every four oxygen atoms. Many minerals have very complex chemical formulas that include several elements.

Explanation:

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A 8kg cat us running 4 m/s. How much kenetic energy is that

Flauer [41]

Using the Definition of Kinetic Energy, we have:

$E_{c}= \frac{mv^2}{2} \\ E_{c}= \frac{8*4^2}{2} \\ \boxed {E_{c}=64J}$

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4 years ago

A taxi

nignag [31]

That taxi will traveled 1500s by carrying the passenger.

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3 years ago

What is Nuclear energy

Yuliya22 [10]

Answer:

Nuclear energy is that released by dividing the nuclei of heavy atoms (also called under the name Nuclear Fission)

Explanation:

In this process, a large amount of heat is generated that can be used to obtain mechanical energy, which is used to generate electrical energy.

Nuclear energy is a sustainable source of energy having a low impact on the environment.

3 0

3 years ago

A 16.5-kg crate starts at rest at the top of a 60.0° incline. The coefficients of friction are μs = 0.400 and μk = 0.300. The cr

irga5000 [103]

Answer:

t = 1.62 s

Explanation:

given,

mass of the block m₁ = 16.5 Kg

m₂ = 8 Kg

angle of inclination = 60°

μs = 0.400 and μk = 0.300

time to slide 2 m = ?

a) let a is the acceleration of the block m₁ downward.

Net force acting on m₂,

F₂ = T - m₂ g

m₂a = T - m₂ g

$a = \dfrac{T}{m_2} - g$ .......(1)

net force acting on m₁

F₁ = m₁g sin(60°) - μ_k m₁g cos (60°) - T

m₁ a = m₁g sin(60°) - μ_k m₁g cos (60°) - T

$a = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}$ .........(2)

from equations 1 and 2

$\dfrac{T}{m_2} - g = g sin(60^0) - \mu_k g cos (60^0) - \dfrac{T}{m_1}$

$\dfrac{T}{m_2} +\dfrac{T}{m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)$

$T\dfrac{m_1+m_2}{m_2\times m_1} = g+ g sin(60^0) - \mu_k g cos (60^0)$

$T = \dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{\dfrac{m_1+m_2}{m_2\times m_1}}$

$T = {m_2\times m_1}\dfrac{g+ g sin(60^0) - \mu_k g cos (60^0)}{{m_1+m_2}}$

$T = {16.5\times 8}\dfrac{9.8 + 9.8 sin(60^0) - 0.3\times 9.8 cos (60^0)}{{16.5+8}}$

T = 90.61 N

from equation (1)

$a = \dfrac{90.61}{8} - 9.8$ .......(1)

a = 1.52 m/s²

let t is the time taken

Apply,

d = ut + 0.5 a t²

2 = 0 + 0.5 x 1.52 x t²

$t = \sqrt{2.63}$

t = 1.62 s

5 0

3 years ago

How do the gravitational and electrical forces between a proton and neutron compare

uysha [10]

Assume distance of seperarion is 1m

F.elec = kQq/r^2

charge of a proton: 1.6×10^-19 C
charge of a neutron: 0 C

F.elec = 0 N

F.grav = GMm/r^2

mass of a proton: 1.672621898×10^-27 kg
mass of a neutron: 1.674927471×10^-27 kg

F.grav = (6.67408×10^-11)×(1.674927471×10^-27)×(1.672621898×10^-27)÷(1^2)

F.grav = 1.8699588×10^-64 N

4 0

4 years ago

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