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iogann1982 [59]
4 years ago
10

What is the most current NASA mission on Mars?

Physics
2 answers:
JulsSmile [24]4 years ago
8 0
The mars rover bot i.e curiosity has been send latestly by NASA on mars. You can also see some pics on net if are doing some project or something.
ivanzaharov [21]4 years ago
3 0
The most recent NASA mission on Mars is Mars Science Laboratory. Its key component was Curiosity rover.
Rover has celebrated his first landing anniversary yesterday (Martian year, that is 687 Earth days).
Curiosity managed to find traces of water on Mars, so it's possible that there used to be some life on Mars.
Since landing Curiosity moved only about 5 miles form the landing site (it suffered wheel damage). 
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You want to examine the hairy details of your favorite pet caterpillar, using a lens of focal length 8.9 cm 8.9 cm that you just
Zepler [3.9K]

Answer:

The angular magnification is M = 2.808

Explanation:

From the question we are told

           The focal length is  f = 8.9cm

          The near point is n_p = 25.0cm

The angular magnification is mathematically represented as

                          M = \frac{n_p}{f}

Substituting values

                        M = \frac{25}{8.9}

                           = 2.808

4 0
3 years ago
Find the horizontal and vertical components of a projectile that is fired with a velocity of 50m/s at 30 degrees relative to the
VashaNatasha [74]
Find this answer on safari and if you can’t reply to me and i’ll help
5 0
4 years ago
1<br> Verify the identity. Show your work.<br><br> cot θ ∙ sec θ = csc θ
Fittoniya [83]
To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ 
sec θ = 1 / cos <span>θ
csc </span>θ = 1 / sin θ<span>

Using these identities:
</span>cot θ ∙ sec θ = (cos θ / sin θ ) (<span> 1 / cos </span><span>θ)
</span>
We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc <span>θ</span>
6 0
4 years ago
A net force of 3 N accelerates a mass of 3 kg at the rate of 1 m/s2. The acceleration of a mass of
Cloud [144]

Answer:

,mkjh ,bkl m,

Explanation:

3 0
4 years ago
Camping equipment weighting 5000N is pulled across a frozen lake by means of a horizontal rope. There is a frictional force of 3
Dmitry [639]

Answer:

The work done by the campers is 4\times10^{5}\ J

(b) is correct option.

Explanation:

Given that,

Weight = 5000 N

Frictional force = 300 n

Distance = 1000 m

Constant rate of speed = 0.20 m/s²

We need to calculate the force

Using newton's law of motion

F-F_{\mu}=ma

F-300=\dfrac{5000}{10}\times0.20

F=\dfrac{5000}{10}\times0.20+300

F=400\ N

We need to calculate the work done

Using formula of work done

W=F\times d

Put the value into the formula

W=400\times1000

W=4\times10^{5}\ J

Hence, The work done by the campers is 4\times10^{5}\ J

3 0
4 years ago
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