Answer:A)For open pipe
1stπ=484cm
2nd wavelength=161.3cm
3rd is=96.8cm
B)For closed pipe
1st wavelength=242cm
2nd=121cm
3rd wavelength=80.7cm
Explanation:
An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...
So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4
π= 121×4=484cm
Third harmonic,L=3π /4
So π= 4l/3=4×121/3=161.3cm
The 3rd wavelength is
Fifth harmonic=
π =4l/5=4×121/5=96.8cm
For a pipe open at one end and closed at the other also called closed pipe
Fundamental note is
2L/n= π where n=1,2,3....ie integers
First wavelength
π=2L=2×121=242cm
Second wavelength
π=L=121cm
Third is
π=2L/3=2×121/3=80.7cm
Answer:
The basic unit of matter is atoms
Answer:
(C) an increase in tue distance between the ibject causes a greater change in the gravitational force than the same increase in mass
Hope this helps
Answer:
All of the above
Explanation:
Astronomers use all of those measures to classify stars. If you want to look more into classifying stars, check out the Hertzsprung-Russel Diagram. It covers how to identify red giants, main sequence, dwarf stars, ect. Distance from earth is typically measured in light years. The color of stars generally determines how hot they are. (Blue stars are the hottest) Also, the parallax method is used to measure stars that are closer to earth. This method relies heavily on geometry though.
Hope this helped!
Answer:
Part a)
a = -9.81 m/s/s
Part b)
v = 0
Part c)
v = 9.81 m/s
Part d)

Explanation:
Part a)
During the motion of ball it will have only gravitational force on the ball
so here the acceleration of the ball is only due to gravity
so it is given as

Part b)
As we know that ball is moving against the gravity
so here the velocity of ball will keep on decreasing as the ball moves upwards
so at the highest point of the motion of the ball the speed of ball reduce to zero

Part c)
We know that the total time taken by the ball to come back to the initial position is T = 2 s
so in this time displacement of the ball will be zero



Part d)
at the maximum height position we know that the final speed will be zero
so we will have

here we have

