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Veronika [31]
3 years ago
12

How is glucose created in plants? Read the choices, select the correct statement.

Chemistry
2 answers:
zhenek [66]3 years ago
6 0

Answer:

the awnser is A

Explanation:

Strike441 [17]3 years ago
4 0
Glucose is created in chloroplasts, (which eliminates A &C) and plants take in CO2, not oxygen, so B is the answer.
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The table below gives some characteristics of element Y what is the identity of element Y
vredina [299]
Where is the table?info given is not enough
8 0
3 years ago
Determine the number of atoms of oxygen present in one mole of nitrogen dioxide?
ValentinkaMS [17]
Di- means 2 so 1 mole of 2 has 2 oxygen atoms
6 0
3 years ago
How many moles of oxygen are needed to produce 2 moles of Tetraphosphorus decaoxide (P4O10) in the reaction?
m_a_m_a [10]

Answer:

C

Explanation:

5 moles of oxygen are needed to produce 1 mols of P4O10

x moles of oxygen are needed to produce 2 mols of P4O10

5/x = 1/2             Cross multiply

1*x = 2 * 5           Combine

x = 10

C

7 0
3 years ago
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶M
zmey [24]

Answer:

HCl is the limiting reactant.

Explanation:

The reactant that yields the lesser number of moles of product is the limiting reactant

Number of moles of MnO2= mass of MnO2/ molar mass of MnO2

Number of moles= 37.7g/86.9368 g/mol= 0.4336 moles

From the reaction equation,

If 1 mole of MnO2 yields 1 mole of chlorine gas

0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas

For HCl

Number of moles of HCl= mass of HCl/ molar mass of HCl

Number of moles= 46.3g/36.46 g/mol = 1.27 moles of HCl

If 4 moles of HCl yields 1 mole of chlorine gas

1.27 moles of HCl will yield 1.27×1/4 = 0.3175 moles of HCl

Hence HCl is the limiting reactant.

8 0
3 years ago
if you replaced the tungsten filament of a typical incandescent bulb with an iron filament, would the emission spectrum be the s
Readme [11.4K]
<span>the electrons change their energy states and photons in visible spectrum (and infrared spectrum) are emitted.More the losses, more would be the light, but at the same time, more would be the heat generated.So this necessitates that the metal used should have high resistivity (and hence high losses), good thermmal conductivity and high melting point.

hope it helps
</span>
4 0
4 years ago
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