Calculate the displacement of the car for the entire trip ( 0s

The angle a vector makes with the x-axis of a coordinate system must be what size in order to make one or more of its components

Aneli [31]

If only 1 option is correct then it is (D)
All the others can also make one component negative, all depends how u measured the angle.
all the best

3 0

2 years ago

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Un avión de rescate en Alaska deja caer un paquete de provisiones a un grupo de exploradores extraviados. Si el avión viaja hori

posledela

Answer:

180.4 m

Explanation:

The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

$V_{ox}=v_x = 40 \ m/s$

h = 100 m

x =?

Height formula h:

$h=g \times \frac{t^2}{2}$

Time t is cleared:

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2 \times 100}{9.8}}$

t = 4.51 sec

Horizontal distance formula x:

$x=V_x \times t$

x = 40 m / sec x 4.51 sec

x = 180.4 m

4 0

2 years ago

A student throws a water balloon with speed v0 from a height h = 1.82 m at an angle θ = 29° above the horizontal toward a target

3241004551 [841]

Answer:

$v_o = 7.76 m/s$

Explanation:

As we projected the balloon at speed vo at an angle of 29 degree

so the two component of velocity is given as

$v_x = v_ocos29 = 0.875 v_o$

$v_y = v_o sin29 = 0.485 v_o$

now we know that in x direction we have

$d = v_x t$

$7.5 = 0.875 v_o t$

$v_o t = 8.57$

in y direction we have

$- 1.82 = (0.485 v_o) t - \frac{1}{2}gt^2$

$-1.82 = 0.485(8.57) - 4.9 t^2$

$t = 1.1 s$

now we have

$v_o = 7.76 m/s$

7 0

2 years ago

100 + 50 + BRAINLIST PLEASE HELP!!!

irina1246 [14]

Answer:

Explanation:

1. What are the forces acting on the block when it is hanging freely from the spring scale? What is the net force on the block? What are the magnitudes of each of the forces acting on the block? Explain.

When a block is hanging freely, two forces are acting on it = tension force from the spring scale and gravity force on the block itself. The net force is zero as the block is not accelerating. The magnitudes of tension and gravity force are the same but in opposite directions.

2. What are the forces that act on the block when it is placed on the ramp and is held in place by the spring scale? What is the net force acting on the block? Explain. (Assume that the ramps are frictionless surfaces.)

There are three forces acting on the block when it is placed on the ramp and is held in place by the spring scale: as in 1, there are tension and gravity but there is a third force - reaction force from the ramp surface on the block that is perpendicular to the surface. Again the block is not moving so the net force is zero.

3. What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces.)

On flat surface, the normal force is equal to the gravity force of the block i.e. its weight. On a vertical surface, the normal force is equal to zero. For the angle of ramp, θ, the normal force = weight * cos θ.

6 0

2 years ago

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Which value is equivalent to 7.2 kilograms? A. 720 grams B. 7,200 grams C. 72,000 grams D. 720 milligrams E. 7,200 milligrams

Aneli [31]

1 kilogram = 1,000 grams
1 kilogram = 1,000,000 milligrams

8 0

2 years ago

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Calculate the displacement of the car for the entire trip ( 0s – 1.1s)