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bulgar [2K]
2 years ago
15

A column of argon is open at one end and closed at the other. The shortest length of such a column that will resonate with a 200

Hz tuning fork is 42.5 cm. The speed of sound in argon must be: Group of answer choices
Physics
1 answer:
ziro4ka [17]2 years ago
7 0

Answer:

The speed of sound in the argon is 340 m/s.

Explanation:

Given;

fundamental frequency, f₀ = 200 Hz

length of the pipe, L = 42.5 cm = 0.425 m

A pipe that is open at one end and closed at another end is known as a closed pipe.

The wavelength for the first harmonic is calculated as;

L = Node -------> Antinode

L = λ/4

λ = 4L

The speed of the sound is calculated as;

v = fλ

where;

v is the speed of the sound

v = f x 4L

v = 200 x (4 x 0.425)

v = 340 m/s

Therefore, the speed of sound in the argon is 340 m/s.

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P_{1} V_{1} =P_{2} V_{2}

Given P_{1} = 1 atm , V_{1} = 15 \ cubic \ meter and P_{2} = 0.75\ atm.

Thus,

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. A laser beam shines along the surface of a block of transparent material (see Fig. E33.8). Half of the beam goes straight to a
Neporo4naja [7]

Answer:

n = 1,875

Explanation:

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          v = d / t

The refractive index of a material is defined by

         n = c / v

         

Let's look for the speed of light in the material, in general the length that light travels is known, this value is high, x = 1, when we place a block on the road, a small amount is lengthened by the length of the block, which in general is despised

These measurements are made on a digital oscilloscope that allows to stop the signals and measure their differences, that is, the zero is taken when the first ray arrives and the time for the second ray is measured,

         

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6 0
3 years ago
Suppose a 4.0-kg projectile is launched vertically with a speed of 8.0 m/s. What is the maximum height the projectile reaches?
eduard

Answer:

h = 3.3 m (Look at the explanation below, please)

Explanation:

This question has to do with kinetic and potential energy. At the beginning (time of launch), there is no potential energy- we assume it starts from the ground. There, is, however, kinetic energy

Kinetic energy = \frac{1}{2}mv^{2}

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Solve = 2(64) = 128 J

Now, since we know that the mechanical energy of a system always remains constant in the absence of outside forces (there is no outside force here), we can deduce that the kinetic energy at the bottom is equal to the potential energy at the top. Look at the diagram I have attached.

Potential energy = mgh = (4.0)(9.8)(h) = 39.2(h)

Kinetic energy = Potential Energy

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Answer:

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