I’m pretty sure it’s NH4, ammonium
Answer:
Oxygen needed for Stannous Oxide: 1.350g
Oxygen needed for Stannic Oxide: 2.710g
Explanation:
You're working with 10.00 grams of Tin mass for both Stannous Oxide and Stannic Oxide.
- 10.00 grams of Tin for Stannous Oxide is already 88.10% of the mass needed. You need to find how much 11.90% of Oxygen mass is needed to create the compound. Find a factor that you can multiply 88.10% by to get 100%
- 88.10 * x = 100
- Solve for x and you get 1.135
- Multiply that number by the mass of Tin (10.00 grams) to get the complete compound (Mixture of Tin and Oxygen).
- 10.00g * 1.135 = 11.35g (Tin + Oxygen)
- Subtract (Compound - Tin) to find Oxygen
- 11.35g - 10.00g = 1.350g (Oxygen)
Repeat the process with Stannic Oxide
- Find the factor that gets 78.70% to 100%
- 100/78.70 = 1.271
- Multiply by Tin mass
- 10.00g * 1.271 = 12.71g (Compound)
- Subtract Compound by Tin
- 12.71g - 10.00g = 2.710g (Oxygen)
len toExplanation:tal esta echpo de los materia
The type of compound is formed between coach and a carboxylic acid alcohol + carboxylic acid → ester + water.
How carboxylic acids are formed?
A acid is produced after the acidic hydrolysis of esters and carboxylates are produced after the basic hydrolysis of an ester.
What are the functional group of alcohol and carboxylic acid?
Alcohols contain the hydroxyl functional group and may be primary, secondary, or tertiary. Ethers are compounds with an oxygen atom bonded to 2 alkyl groups. Aldehydes and ketones contain the carbonyl functional group
Can a compound be a acid and an alcohol?
Esters are represented by the formula RCOOR', where R and R' are hydrocarbon groups. The ester, which is compound derived from a carboxylic acid and an alcohol in which the OH of the acid is replaced by an OR group, looks somewhat sort of a n ether and also somewhat like a carboxylic acid.
Learn more about carboxylic acid :
brainly.com/question/15942533
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