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swat32
3 years ago
13

Help me please,

Physics
1 answer:
garik1379 [7]3 years ago
7 0

Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

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A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th
Vesna [10]

Answer:

Average speed of car will be 48 km/hr  

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance t_1=\frac{d}{40}hr

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance t_2=\frac{d}{60}hr

So total time to cover 2d distance t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}

Average speed is the ratio of total distance to total time

So average speed =\frac{2d}{\frac{5d}{120}}=48km/hr

So average speed of car will be 48 km/hr

4 0
3 years ago
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
GalinKa [24]

Answer:

The electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε = 8.8542 * 10^{-12}

Substitute ε = 8.8542 * 10^{-12} and q =7.6\µC; The formula becomes

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

Ф = 8.58 *10^{5} \frac{Nm^2}{C}

Hence, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

7 0
3 years ago
⚠️ PLEASE HELP ⚠️
Svetllana [295]

Answer:

-79.6

-80

-81.2

Explanation:

5 0
3 years ago
Read 2 more answers
An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
sergiy2304 [10]

To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.

Mathematically this pressure is given under the formula

P_h = \rho g h

Where,

\rho = Density

h = Height

g = Gravitational acceleration

Rearranging in terms of g

g = \frac{P_h}{\rho h}

our values are given as

P_h = 1.1 atm (\frac{101325Pa}{1atm}) = 111457.5Pa

\rho = 1000kg/m^3

h = 12.3m

Replacing we have

g = \frac{111457.5}{(1000)(12.3)}

g = 9.061m/s^2

Therefore the gravitational acceleration on the planet's surface is 9.061m/s^2 (Almost the gravity of the Earth)

3 0
3 years ago
The best method for separating an oil and water mixture would be _____.
Mice21 [21]

Answer:

The answer is density

Explanation:

8 0
3 years ago
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