What two variables is acceleration dependent on?

A beam of light strikes a sheet of glass at an angle of 57.0°. with the normal in air. You observe that red light makes an angle

Lena [83]

Answer:

a) Red: 1.34

Violet: 1.40

b) Red: $2.23\times10^8\frac{m}{s}$

Violet: $2.14\times10^8\frac{m}{s}$

Explanation:

a) We should use Snell's law to find the index of refraction:

$n_{1}sin\theta_{i}=n_{2}sin\theta_{t}$

with n1 the index of refraction of air, n2 the index of refraction of the glass, θi the angle of the incident ray respects the normal an θt the angle between the refracted ray an the normal. It's common to approximate n1=1

solving n2 for red light:

$\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}$

$n_2=\frac{sin57.0}{sin38.1}= 1.34$

solving n2 for violet light:

$\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}$

$n_2=\frac{sin57.0}{sin36.7}= 1.40$

b) Index of refraction on a medium is defined as the ratio between the velocity of electromagnetic waves on vacuum (velocity of light c) and the velocity in medium (v):

$n_2=\frac{c}{v}$

solving v for red:

$v=\frac{c}{n_2}=\frac{3\times10^8}{1.34}=2.23\times10^8\frac{m}{s}$

solving v for violet

$v=\frac{c}{n_2}=\frac{3\times10^8}{1.40}=2.14\times10^8\frac{m}{s}$

8 0

3 years ago

HELP as shown in the diagram, points p,q, and r are located near a positively charged object.

tester [92]

I can’t open or look at the image

6 0

3 years ago

A car traveling 25 m/s to the north collides with a car traveling 15 m/s to the south. Each car has a mass of 1100 kg. If the sy

kirill [66]

conservation of momentum ... that before = that after ... change zero

8 0

3 years ago

Read 2 more answers

A rock band playing an outdoor concert produces sound at 120 dB 5.0 m away from their single working loudspeaker. What is the so

joja [24]

ANSWER:100dB

from the sound intensity level,the sound intensity is calculated as:

$\beta$ ₁= $\beta$ =(10dB)㏒₁₀(l₁/l₀)

inserting numbers:

120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²

Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which

can be used to solve for l₁ and get

l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²

since the sound intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in

ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:

l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²

since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:

$\beta$ ₂= $\beta$ =(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)

$\beta$ ₂=(10dB)㏒₁₀(2.04×10¹⁰)

$\beta$ =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB

3 0

4 years ago

What occurs to the arrangement of water molecules as water melts

Nikolay [14]

The arrangements of the water molecules they begin to spread apart. As the water(ice) melts the molecules develop fewer compact and start juddering harder until the ice has changed state into liquid.

7 0

3 years ago

Read 2 more answers