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MatroZZZ [7]
4 years ago
8

What two variables is acceleration dependent on?

Physics
1 answer:
Vaselesa [24]4 years ago
7 0
The correct answer to this qustion is velocity and time
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Im not sure how to figure this circuit out
vredina [299]

Yes, this is certainly ugly and scary.
Here's how to go about it:

-- Take the two resistors in the middle ... the  9  and the  8 .
   They're in parallel.
   Their equivalent resistance is something like 4.24 ohms.  Whatever.

-- Take the two resistors around the outside on the right ... the 4 and the 6 .
    Together, in series, they're equivalent to  10 ohms.

-- That 10 ohms is in parallel with the ~4.24 ohms in the box.
    Now you have something like  2.98 ohms, all to the right of the 3 on top.

--  That 2.98 is in series with the 3.0 on top.
     So there's  5.98 ohms.

-- The 20.0 is in parallel with the  5.98 ohms.
    So that's about 4.6 ohms equivalent between 'A' and 'B'.

That's just off the top of my head.  I won't sharpen it down
any further than that, because it's only 5 points, and you
should be able to do it now, using this approach.

3 0
3 years ago
A 790N person runs up a flight of 40 stairs (.25m for each step) in 20 seconds, and then down 10 steps in 5 seconds. How much to
Romashka [77]

A person runs up 40 stairs and then come down 10 steps

So total stairs upwards is given as

N = 40 - 10 = 30

now here we will have total height reached

H = N\times h

H = 30 \times 0.25 = 7.5 m

Now total energy used or mechanical work done is

W = mgH

W = 790 \times 7.5 = 5925 J

Now the mechanical power is given as

P = \frac{W}{t}

P = \frac{5925}{20+ 5} = 237 W

7 0
3 years ago
What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=
zalisa [80]

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

7 0
3 years ago
How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?
Crazy boy [7]
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
8 0
3 years ago
Please i need the answer of this question
frez [133]

Answer:

i think it is f i could be wrong-

6 0
3 years ago
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