Question

(eopt)s. Find the power dissipated in a 25 r heaterconnected to a 220V outer.​

Answer 1

Answer:

P = 1936 W

Explanation:

Given that,

Voltage, V = 220 V

The resistance of the heater, R = 25 ohms

We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :

$P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W$

So, the required power is equal to 1936 W.