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patriot [66]
3 years ago
5

(eopt)s. Find the power dissipated in a 25 r heaterconnected to a 220V outer.​

Physics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

P = 1936 W

Explanation:

Given that,

Voltage, V = 220 V

The resistance of the heater, R = 25 ohms

We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :

P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W

So, the required power is equal to 1936 W.

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Answer:

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Explanation:

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<h2> </h2>

<h2>formula = ( F=ma </h2>

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