and closing
.
The heart has 4 valves. They are what makes the lub-dub lub-dub sounds that can be heard from the chest.
The mitral valve is located between the left atrium and the left ventricle. It closes the left atrium to collect oxygenated blood from the lungs and opens to pass it on to the left ventricle.
The tricuspid valve is located between the right atrium and the right ventricle. It closes the right atrium to hold unoxygenated blood and opens to pass it on to the right ventricle ensuring a one way flow.
The aortic valve is located between the aorta and the left ventricle. It closes the left ventricle and opens to the aorta to pass on the oxygen-rich blood to the body.
The pulmonary valve is located between the pulmonary artery and the right ventricle. It closes off the right ventricle and opens to pass on unoxygenated blood to the lungs.
Answer:
Saturn's differential rotation will cause the length of a day measures to be longer by 0.4 hours
Explanation:
Differential rotation occurs due to the difference in angular velocities of an object as we move along the latitude of the or as we move into different depth of the object, indicating the observed object is in a fluid form
Saturn made almost completely of gas and has differential motion given as follows
Rotation at the equator = 10 hours 14 minutes
Rotation at high altitude = 10 hours 38 minutes
Therefore;
The differential rotation = 10 hours 38 minutes - 10 hours 14 minutes
The differential rotation = 24 minutes = 24 minutes × 1 hour/(60 minutes) = 0.4 hours
The differential rotation = 0.4 hours
Therefore, the measured day at the higher altitude will be 0.4 longer than at the equator.
Homie I don’t know either♀️Drop out of schl ig ;-;
Answer:
Radiation
Explanation:
The sun energy reaches us by Radiation.
Answer: a) - 437.8° F, b) - 261°c.
Explanation: a) the kelvin and Fahrenheit temperature scale are related by the formulae below.
5 (°F - 32) = 9 (k - 273)
Where °F = temperature in Fahrenheit and k = temperature in kelvin.
For question A, k = 12.0, by substituting to have the value for °F, we have
5(°F - 32) = 9 ( 12 - 273)
5(°F - 32) = 9(-261)
5(°F - 32) = - 2349
°F - 32 = - 2349/5
°F - 32 = - 469.8
°F = - 469.8 + 32
°F = - 437.8
Question B
The centigrade and kelvin scale are related by the formulae below
°c = k - 273
Where °c = temperature in centigrade and k = temperature in kelvin =12
°c = 12 - 273
°c = - 261
