Answer: 14.16
Explanation:
Given
d = 38cm
r = d/2 = 38/2 = 19cm = 0.19m
K.E = 510J
m = 10kg
I = 1/2mr²
I = 1/2*10*0.19²
I = 0.18kgm²
When it has 510J of Kinetic Energy then,
510J = 1/2Iω²
ω² = 1020/I
ω² = 1020/0.18
ω² = 5666.67
ω = √5666.67 = 75.28 rad/s
Velocity is the block, v = ωr
V = 75.28 * 0.19
V = 14.30m/s
The "effective mass" M of the system is
M = (14.0 + ½*10.0) kg = 19.0 kg
The motive force would be
F = ma
F = 14 * 9.8
F = 137.2N
so that the acceleration would be
a = F/m
a = 137.2/19
a = 7.22m/s²
Finally, using equation of motion.
V² = u² + 2as
14.3² = 0 + 2*7.22*s
204.49 = 14.44s
s = 204.49/14.44
s = 14.16m
Explanation:
given,
mass of one planet (m1)=2*10^23 kg
mass of another planet (m2)=5*10^22kg
distance between them(d)=3*10^16m
gravitational constant(G)=6.67*10^-11Nm^2kg^-2
gravitational force between them(F)=?
we know,
F=Gm1m2/d^2
or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2
or, F=6.67*2*5*10^-11+23+22/3*3*10^32
or, F=66.7*10^34/9*10^32
or, F=7.41*10^34-32
•°• F=7.41*10^2
thus, the gravitational force between them is 7.14*10^2
Answer:
Frequency is the number of wavelengths, which is measured in hertz.
Explanation:
I have my ways ;)
