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3 years ago

What mass of NaOH do you need to dissolve in 500ml of solution to obtain a 0.6mol / l solution?

Chemistry

1 answer:

lara31 [8.8K]3 years ago

3 0

Mass of NaOH required = 12 g

<h3>Further explanation</h3>

Given

500 ml solution = 0.5 L

Molarity = 0.6 mol / L

Required

mass of NaOH

Solution

Molarity = moles of solute per liter of solution

M = n / V

solute = NaOH

moles of solute = n = M x V

n = 0.6 x 0.5

<em>n = 0.3 moles</em>

Mass of NaOH = mol x MW

mass = 0.3 x 40 = 12 g

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3 years ago

Aluminum bronze contains 92.0% copper and 8.0% aluminum. What maximum mass of aluminum bronze can be prepared from 73.5g of copp

Keith_Richards [23]

The ratio of aluminum bronze components is:

92.0 Cu / 8.0 Al

The ratio of Cu and Al avilable is: 73.5 Cu / 42.2 Al

Then, it is evident that Al is in excess and Cu is the limitant material.

So, you need two work with the open proportion 92.0/ 8.0 = 73.5Cu / x

=> x = 73.5 * 8 / 92 = 6.39

Then, you can use 6.4 grams of Al and 73.5 grams of Cu to prepare 6.39g + 73.5g = 79.89.grams of Bronze.

I hope this helps.

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3 years ago

____________Polar regions get less of the sun's direct rays, they are the coldest climates on Earth. A because , B although, C H

Roman55 [17]

Answer:

Because Polar regions get less of the sun's direct rays, they are the coldest climates on Earth.

Explanation:

5 0

3 years ago

A sample of krypton gas collected at a pressure of 1.31 atm and a temperature of 26.0°C is found to occupy a volume of 23.3 lite

djyliett [7]

Mol of Kr gas = 1.244

<h3>Further explanation</h3>

In general, the gas equation can be written

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08205 L.atm / mol K

T = temperature, Kelvin

P=1.31 atm

V=23.3 L

T=26+273=299 K

mol of sample :

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3 0

3 years ago

In the laboratory you dissolve 22.0 g of nickel(II) nitrate in a volumetric flask and add water to a total volume of 125

Ahat [919]

Answer:

<u>1.364 M</u>.

Explanation:

Molarity formula: M= n/v, where n is moles of solute, and v is liters of solution.

Now, we need to convert the grams of nickel to moles and the volume of water to liters.

125mL/1000= 0.125 L.

To convert nickel grams to moles, we need to take a look at it's chemical formula, which is:

$Ni(NO_{3} )_{2}$

Now we count how many molecules of each element we have:

Ni= 1

N= 2

O= 6

Calculate the weight (g) of each element (the values of g/mol can be found on the periodic table and they may vary slightly between one table and the other):

Ni: (1) (58.6934)= 58.6934

N= (2) (14.007)= 28.014

O= (6) (15.999)= 95.994

Sum all the values to obtain the total weight of 1 mole of this compound:

58.6934+28.014+95.994= 129(g/mole)

Now that we know the that 129 grams equal 1 mole of nickel(II) nitrate, we can convert the 22.0 g to moles:

129g ------- 1 mole

22.0g ----- x

x= (22*1)/129= 0.1705 moles.

Now, we have all the values needed to calculate the molarity of this solution. All we have to do is substitute the values in the formula:

M= (0.1705 moles) / (0.125 L)= <u>1.364 M</u>.

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2 years ago