Answer:
Periodic but not oscillatory
Explanation:
The Orbital motion of the earth around the sun is not an oscillatory motion as it is not a two and Fro motion about a mean position. But it is a periodic motion.
Answer:
It is <em><u>photosynthesis</u></em><em><u> </u></em><em><u>and </u></em><em><u>transpiration</u></em><em><u> </u></em>
hope it helps
Answer:
Keqq = 310
Note: Some parts of the question were missing. The missing values are used in the explanation below.
Explanation:
<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>
Using the formula ΔG° = -RT㏑Keq
㏑Keq = ΔG°/(-RT)
where ΔG° = ΔH° - TΔS°
㏑Keq = ΔH° - TΔS°/(-RT)
㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)
㏑Keq = -14221.2/-2478.968175
㏑Keq = 5.73674166
Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶
Keq = 310.05
The answer is Doppler Radar. Hope this helps!
Over 344.76 K the forward reaction will be spontaneous
<u><em>calculation</em></u>
ΔG = ΔH° -TΔs
if ΔG =0
therefore 0 =ΔH°-TΔs
ΔH° = TΔs
divide both side by Δs
T = ΔH°/Δs
convert 34.2 kj into j
that is 1 kj = 1000 j
34.2 kj =? j
<em>by cross multiplication</em>
=[34.2 kj x 1000j / 1 kj] = 34200 j
T is therefore = 34200 j÷99.2 j/k =344.76 k
if T is greater than 344.76 k the forward reaction will be spontaneous