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SIZIF [17.4K]
3 years ago
8

During chemical weathering, forsterite is dissolved by the carbonic acid in rainwater. The weathering reaction is as follows:

Chemistry
1 answer:
Semenov [28]3 years ago
4 0

Answer:

Keqq = 310

Note: Some parts of the question were missing. The missing values are used in the explanation below.

Explanation:

<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>

Using the formula ΔG° = -RT㏑Keq

㏑Keq = ΔG°/(-RT)

where ΔG° = ΔH° - TΔS°

㏑Keq = ΔH° - TΔS°/(-RT)

㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)

㏑Keq = -14221.2/-2478.968175

㏑Keq = 5.73674166

Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶

Keq = 310.05

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What is one substance that is 100x more acidic than baking soda
daser333 [38]

Answer:

An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution. This kind of solution is acidic.

Explanation:

8 0
2 years ago
1.Using the absorbance of the spinach extract and the equation of the trendline, determine the concentration of the extract solu
lys-0071 [83]

Answer:

Explanation:

From the given information:

We are to make use of the spinach absorbance extract which is the corrected absorbance  (y) = 0.306

And also the trendline equation:

y = 1609x + 0.0055

where,

x = absorbance of the spinach extract.

∴

0.306 = 1609x + 0.0055

collecting the like terms

0.306 - 0.0055 = 1609x

0.3005  = 1609x

x = 0.3005/1609

x = 1.8676 × 10⁻⁴

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No. of grams for the chlorophyll can be computed as follows:

recall that:

molar mass of chlorophyll = 893.5 g/mol

the volume = 25ml = (25/1000) L = 0.025 L

∴

In spinach solution, the no. of grams for the chlorophyll:

= (0.0002) mol/L × (893.5 g/mol) × (0.025) L

= 0.0044675 g

≅ 0.0045 g

In the spinach, the concentration of chlorophyll = no of grams of chlorophyll/ mass of the spinach

= 4.5 mg/0.1876 g

= 23.987 mg/g

≅ 24 mg/g

4 0
2 years ago
Please help !!! 45 minutes remaining on my test
Ksivusya [100]
First, third, last one I had the same test
7 0
3 years ago
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Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.2HgO Righ
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Answer: 15.62 moles of HgO are needed to produce 250.0 g of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{250.0g}{32g/mol}=7.812moles

2HgO\rightarrow 2Hg+O_2

According to stoichiometry :

1 mole of O_2 is produced from decomposition of =  2 moles of HgO

Thus 7.812 moles of O_2 will be produced from decomposition of  =\frac{2}{1}\times 7.812=15.62moles of HgO

Thus 15.62 moles of HgO are needed to produce 250.0 g of O_2

7 0
3 years ago
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