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elena-s [515]
3 years ago
6

When the voltage is

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Explanation:

ask to nirajan shrestha

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When would the displacement technique of measuring need to be employed?
Tanzania [10]

Answer:

a is the answer is yes I....

Explanation:

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5 0
3 years ago
What causes convection currents, and what do they do?
frez [133]

Answer:

Convection currents are the result of different heating. Lighter material (warm) rises while heavier (cold) material sinks. This movement of the materials is what causes convection currents! (BTW, it happens in water, in the atmosphere, and in the mantle of Earth!

Explanation:

I hope this helps a little! :)

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3 years ago
when you place your feet near the fireplace and they become warm what type of energy conversion occurs
JulsSmile [24]
I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. "Radiant to thermal" is the type of energy conversion that occurs when <span>you place your feet near the fireplace and they become warm. I hope the answer has come to your great help.</span>
8 0
4 years ago
Read 2 more answers
An aluminum bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 40mm in diameter and 10
s2008m [1.1K]

Answer:

<em>1.228 x </em>10^{-6}<em> mm </em>

<em></em>

Explanation:

diameter of aluminium bar D = 40 mm  

diameter of hole d = 30 mm

compressive Load F = 180 kN = 180 x 10^{3} N

modulus of elasticity E = 85 GN/m^2  = 85 x 10^{9} Pa

length of bar L = 600 mm

length of hole = 100 mm

true length of bar = 600 - 100 = 500 mm

area of the bar A = \frac{\pi D^{2} }{4} =  \frac{3.142* 40^{2} }{4} = 1256.8 mm^2

area of hole a = \frac{\pi(D^{2} - d^{2}) }{4} = \frac{3.142*(40^{2} - 30^{2})}{4} = 549.85 mm^2

Total contraction of the bar = \frac{F*L}{AE} + \frac{Fl}{aE}

total contraction = \frac{F}{E} * (\frac{L}{A} +\frac{l}{a})

==> \frac{180*10^{3}}{85*10^{9}} *( \frac{500}{1256.8} + \frac{100}{549.85}) = <em>1.228 x </em>10^{-6}<em> mm </em>

6 0
3 years ago
(3.16_Q2) Which weights would you use on a single thread to create a 6.86 N force? Question 2 options: Weight IDs A, B, C, D Wei
Tomtit [17]

1. E,F

2. D,E,F

3. B,C,E,G

4. A,B,C,D

I did the test! :)

5 0
3 years ago
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