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Molodets [167]
2 years ago
14

12. Energy from the breaking of atomic bonds in molecules (ex: C4 explosion)

Physics
1 answer:
Korolek [52]2 years ago
6 0

Answer:

endothermic energy or chemical energy

Explanation:

An endothermic process increases the enthalpy H of the system, during which the closed system (usually) absorbs thermal energy from its surroundings.

Chemical energy is the form of potential energy in which energy is stored in chemical bonds. The breaking of chemical bonds absorbs energy, while the formation of new bonds releases energy.

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but that's just what I think

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What is the final speed?
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Ball A is dropped from the top of a building of height h at the same instant that ball B is thrown vertically upward from the gr
DiKsa [7]

Answer:

(2/3) times height collision occur

Explanation:

for ball A

from the kinematic equation

the distance of ball A is

x_A = v_0 t + \frac{1}{2} at^2

v_0* t= velocity ( time ) = distance

since ball is at height, the above equation changes as

x_A = H - \frac{1}{2} gt^2

for ball B

xB = v0 t - \frac{1}{2} gt^2

the condition of collision is

xA = xB

vA = - 2vB (given)

from the kinematic equation

the speed of the ball A is

v_A = u- gt

since initial speed of the ball A is zero

, so

v_A = -gt

the speed of the ball B is

v_B = v_0 - gt

sincev_A = - 2v_B

   -gt = -2 ( v_0 - gt)

-gt = -2 v_0 +2gt

3gt =2 v_0

t = \frac{2v_0}{3g}

since x_A = x_B

H -  \frac{1}{2} gt^2= v_0 t - \frac{1}{2} gt^2

H = v_0 t

= v_0 (2v_0/3g)

= \frac{2 v_0^2}{ 3g}

x_A = 2 (\frac{v_0^2}{ 3g})- \frac{1}{2} gt^2

  = 4 \frac{v_0^2}{9g} = (2/3) H

so, (2/3) times height collision occur

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3 years ago
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