Answer:
The answer is 138.5
Explanation:
STEP 1:
The inductance per unit length of a coaxial transmission line is
L′=L<em>/ </em>I
=Ø/H
=μoI/2π In (b/a)
In this a is the radius of inner conductor
b is the radius of outer conductor
I is the coaxial transmission
μ is the magnetic permeability
Since the transmission of the charge exists in air, the value of the relative permeability is μr= I and permeability of free space is μo= 4π x 10-7 H/m . So the magnetic permeability will be
μ = μoμ r
μ =μ o(I) 4π x 10-7 H/m
L′= μoI/2π In (b/a)
= (4π x 10-7 ) (2)/2π In (10/5)
=2.77 x 10-7 H
STEP 2:
Obtain the magnetic energy stores in the magnetic field H of a volume of the coaxial transmission line containing a material with permeability μ, by using the formula given below:
Wm= 1/2 LI^2
= 1/2 (2.77x 10^-7 I^2
= 138.5 X 10^-9 I^2 J
Now we will simplify the equation
Wm= 185.5<em>I</em>^2 nJ
So, the magnetic energy stored in insulating medium is 185.5<em>I</em>^2 nJ
Answer:
Orbital
Explanation:
The orbitals is the area or region outside the nucleus where an electron can most likely be found
<span> A. 6,000,000 Hz =3 they were correct</span>
For the answer to the question above, i<span>n </span>direct current<span> (</span>DC<span>), the </span>electric charge<span> (</span>current)only flows<span> in one direction. </span>Electric charge<span> in alternating </span>current<span> (AC), on the other hand, changes direction periodically. The voltage in AC circuits also periodically reverses because the </span>current<span> changes direction. So my answer is A.</span>