Yea um this is definitely confusing help anyone??

Pete can run 178 yards in one minute. Sharon can run 119 more yards then Pete in one minute how many yards can they both run in

worty [1.4K]

Answer:

495

Step-by-step explanation:

pete=178

sharon=178+119=297

297+178=495

5 0

3 years ago

Help me please , Write the slope intercept of the given line, provide the submit solution

Dmitry [639]

Answer:

y=1/3x + 2

Step-by-step explanation:

the y intercept is 2 since that's where the line crosses and the x intercept is at 4

6 0

2 years ago

A football team plays in a large stadium. With a ticket price of $19, the average attendance at recent games has been 50 comma

tino4ka555 [31]

Answer:

Part 1: N(x) = 50,000 - 300(x-19)

Part 2: R(x) =-300x² + 55700x

Step-by-step explanation:

Given,

The original price of each ticket = $ 19,

The original attendance = 50,000

Part 1 :

∵ For the each $1 increase in the ticket price, attendance decreases by 300.

Let x represents the price of each ticket after increment,

Thus, if price increment = (x-19) dollars,

New attendance, N(x) = 50,000 - 300(x-19)

Part 2 :

Since, revenue = price of each ticket × attendance

Thus, the revenue from the football game,

R(x) = x(50,000 - 300(x-19))

R(x) = 50000x - 300x²+ 5700x

⇒ R(x) =-300x² + 55700x

8 0

4 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that $n = 292, \pi = \frac{52}{292} = 0.178$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207$

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

3 0

3 years ago

How many solutions does the equation 2(x-5)=2x+3

Stella [2.4K]

2(x-5)=2x+3
2x-10=2x+3
2x=2x+13
0x=13
x=0
There are no solutions (13/0 is 0)

5 0

3 years ago