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juin [17]
3 years ago
10

I pull a wagon with a 30 kg child in it with a FORCE of 2000 N. The handle makes a 60 degree angle with the horizon. If I pull t

he child for a distance of 0.75 miles (1 mile = 1600 m), how much work did I do?
Physics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

1200000 J

Explanation:

Applying,

W = Fdcos∅....................... Equation 1

Where W = Workdone, F = Force applied to pull the wagon, d = distance, ∅ = angle with the horizontal.

From the question,

Given: F = 2000 N, d = 0.75 miles = (0.75×1600) = 1200 m, ∅ = 60°

Substitute these values into equation 1

W = 2000×1200×cos60°

W = 2000×1200×0.5

W = 1200000 J

Hence the work done in pulling the wagon is 1200000 J

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Determine the amount of work done on an ideal gas as it is heated in an enclosed thermally insulated cylinder topped with a free
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Explanation:

Let's use the first law of thermodynamics

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we substitute

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3 years ago
Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at t
slava [35]

Answer:

Part A

1) At the starting point, we have;

PE = 40,000 J

2) PE = 0 J, KE = 40,000 J

3) KE = 20,000 J

4) PE = 15,000 J

5) KE = 32,500 J

6) KE = 40,000 J, PE = 0 J

7) KE = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The total Mechanical Energy = ME = 40,000 J

At the final point, we have;

ME = KE + PE = 40,000 J + 0 J = 40,000 J

Explanation:

Part A

By the law of conservation of energy, we have;

ME = PE + KE

Where;

ME = The total Mechanical Energy of the system

PE = The Potential Energy of the system

KE = The Kinetic Energy of the system

Where there is no friction, we have;

At the final stage, KE = 40,000 J. PE = 0 J

Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J

1) At the starting point, we have;

KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J

2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;

PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J

3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J

4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J

5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J

6) At the bottom KE = 40,000 J, PE = 0 J

7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;

ME = KE + PE

At the final point, we have;

ME = 40,000 J + 0 J = 40,000 J

The total Mechanical Energy = ME = 40,000 J

8 0
2 years ago
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