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3 years ago

Can different masses have the same kinetic energy?

Physics

1 answer:

skelet666 [1.2K]3 years ago

8 0

Yes.objects of different masses can have the same kinetic energy

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An apple has 6 J of energy. The apple sits on a counter 3 m high. What is the mass of the apple?

Reika [66]

Explanation:

PE= mgh

6 J= (3m) (9.81 m/s2) (mass)

mass=( 6)/(3×9.81)

mass= 0.20 Kg

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3 years ago

How do you determine the acceleration of an object?

Gelneren [198K]

Are you familiar with any basic calculus? If so, we can just look at this derivative and see what's happening with our units here..

$a = \frac{dv}{dt}$

Here it shows that acceleration is the derivative of velocity with respect to time. In other words, we can say that:

$a=\frac{\Delta v}{\Delta t}$

We can read that equation as: "acceleration is the change of velocity divided by the change in time (aka the time interval)."

If you're not familiar with calculus, we can use a simple equation of motion:

$v_f = v_i+at$

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = observed time interval

We can rearrange this equation to find:

$a = \frac{v_f - v_i}{t}$

This is the same exact thing we wrote before!

8 0

3 years ago

Read 2 more answers

A nichrome wire and an aluminum wire, each with the same initial resistance, have the same change in resistance when heated sepa

Svetach [21]

Answer:

The ratio of temperature change of nichrome wire to the temperature change of aluminum wire is found to be <u>9.75</u>

Explanation:

The change in resistances and initial resistances of the wires are:

Change in Resistance of Nichrome Wire = ΔR₁

Change in Resistance of Aluminum Wire = ΔR₂

Initial Resistance of Nichrome Wire = R₁

Initial Resistance of Aluminum Wire = R₂

Also, it is given that the change in resistance and initial resistance of both wires is equal. Therefore,

ΔR₁ = ΔR₂ ---------- eqn (1)

R₁ = R₂ ---------- eqn (2)

The change in Resistance due to temperature is given by formula:

ΔR = R α ΔT

Therefore, eqn (1) becomes:

R₁ α₁ ΔT₁ = R₂ α₂ ΔT₂

using eqn (2):

α₁ ΔT₁ = α₂ ΔT₂

ΔT₁/ΔT₂ = α₂/α₁

where,

α₁ = Temperature coefficient of resistance of nichrome = 0.4 x 10⁻³ °C⁻¹

α₂ = Temperature coefficient of resistance of aluminum = 3.9 x 10⁻³ °C⁻¹

Therefore,

ΔT₁/ΔT₂ = (3.9 x 10⁻³ °C⁻¹)/(0.4 x 10⁻³ °C⁻¹)

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4 years ago

1. Name two ways of applying forces ?

Anna007 [38]

Answer: A force can be applied to another object by a direct push, pull, or drag.

Explanation:

4 0

3 years ago

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Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented

Svetlanka [38]

Answer:

$\theta = 0.195^0$

Explanation:

wavelength $\lambda = 648 nm \ = 648*10^{-9}m$

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

$dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})$

$\theta = 0.195^0$

The first maximum will appear at an angle $\theta = 0.195^0$ from the beam axis

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3 years ago