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Kamila [148]
2 years ago
5

Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the eq

uator to the North Pole.
Physics
2 answers:
Kisachek [45]2 years ago
8 0

Answer:

False

Explanation:

It is actually the exact opposite.

Vinil7 [7]2 years ago
3 0

Answer:

Explanation:

Yes, If tangential velocity is your reference frame

If R is the radius of earth

and ω is the angular velocity = (2π / (24(3600)) radians/s

Tangential velocity at the equator is

v = ωR = (2π / (24(3600))(6 370 000 m) = 463 m/s

Tangential velocity at a point half way to the pole (45° latitude)

v = ωRcosΘ = 463cos45 = 328 m/s

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3 years ago
A cannon is fired horizontally at 243 m/s off of a 62 meter tall, shear vertical cliff. How far in meters from the base of the c
Alekssandra [29.7K]

Answer:

865.08 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 243 m/s

Height (h) of the cliff = 62 m

Horizontal distance (s) =?

Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:

Height (h) of the cliff = 62 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

62 = ½ × 9.8 × t²

62 = 4.9 × t²

Divide both side by 4.9

t² = 62/4.9

Take the square root of both side.

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Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:

Initial velocity (u) = 243 m/s

Time (t) = 3.56 s

Horizontal distance (s) =?

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Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.

6 0
2 years ago
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