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Kamila [148]
3 years ago
5

Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the eq

uator to the North Pole.
Physics
2 answers:
Kisachek [45]3 years ago
8 0

Answer:

False

Explanation:

It is actually the exact opposite.

Vinil7 [7]3 years ago
3 0

Answer:

Explanation:

Yes, If tangential velocity is your reference frame

If R is the radius of earth

and ω is the angular velocity = (2π / (24(3600)) radians/s

Tangential velocity at the equator is

v = ωR = (2π / (24(3600))(6 370 000 m) = 463 m/s

Tangential velocity at a point half way to the pole (45° latitude)

v = ωRcosΘ = 463cos45 = 328 m/s

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siniylev [52]
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4 0
3 years ago
One baked potato provides an average of 30 mg of vitamin C. If 70 potatoes weigh 20 lb., how many milligrams of vitamin C are pr
JulsSmile [24]

Answer:

105 mg

Explanation:

Given that:

1 baked potato provides 30 mg of vitamin C.

So,

70 baked potatoes provide 30\times 70 mg of vitamin C

Also,

70 potatoes = 20 lb

So,

20 lb potatoes provide 30\times 70 mg of vitamin C

Thus,

1 lb potatoes provide \frac {30\times 70}{20} mg of vitamin C

<u>Thus, 105 mg of Vitamin C are provided per pound of the potatoes.</u>

5 0
3 years ago
A police radar gun uses X-band microwave radiation at a frequency of 12.2 GHz. Microwaves travel at the speed of light, or 3x108
quester [9]

Answer:

A police radar gun uses X-band microwave radiation at a frequency of 13.1 GHz. Microwaves travel at the speed of light, or 3x108 m/s. Since the frequency shift will be small for practical car speeds and difficult to detect, the shifted frequency is compared to the original frequency, and the resulting beat frequency is used to determine the speed of the car.

a.) If Michael is traveling at 29 m/s, what is the resulting beat frequency that the radar gun detects?

ANSWER: 2533 Hz

Explanation:

6 0
3 years ago
On Earth, 1 kg = 9.8 N = 2.2 lbs. On the Moon, 1 kg = 1.6 N = 0.37 lbs. Use these relationships to answer the following question
romanna [79]

Answer:

(a) 490 N on earth

(b) 80 N on earth

(c) 45.4545 kg on earth

(d) 270.27 kg on moon

Explanation:

We have given 1 kg = 9.8 N = 2.2 lbs on earth

And 1 kg = 1.6 N = 0.37 lbs on moon

(a) We have given mass of the person m = 50 kg

As it is given that 1 kg = 9.8 N

So 50 kg = 50×9.8 =490 N

(b) Mass of the person on moon = 50 kg

As it is given that on moon 1 kg = 1.6 N

So 50 kg = 50×1.6 = 80 N

(c) We have given that weight of the person on the earth = 100 lbs

As it is given that 1 kg = 2.2 lbs on earth

So 100 lbs = 45.4545 kg

(d) We have given weight of the person on moon = 100 lbs

As it is given that 1 kg = 0.37 lbs

So 100 lbs \frac{100}{0.37}=270.27kg

8 0
3 years ago
You have four fixed-volume containers at STP . Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L.
Colt1911 [192]

Answer:

Container A and C

Explanation:

ideal gas equation gives P=nRT/V

so at constant Temperature and pressure, P=n/T

Container A and C after dividing number of moles and Volume, are found to be the same=0.0446

8 0
3 years ago
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