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Kamila [148]
3 years ago
5

Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the eq

uator to the North Pole.
Physics
2 answers:
Kisachek [45]3 years ago
8 0

Answer:

False

Explanation:

It is actually the exact opposite.

Vinil7 [7]3 years ago
3 0

Answer:

Explanation:

Yes, If tangential velocity is your reference frame

If R is the radius of earth

and ω is the angular velocity = (2π / (24(3600)) radians/s

Tangential velocity at the equator is

v = ωR = (2π / (24(3600))(6 370 000 m) = 463 m/s

Tangential velocity at a point half way to the pole (45° latitude)

v = ωRcosΘ = 463cos45 = 328 m/s

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Answer:

The thinking distance depends on the reaction time of the driver which could can affected by alcohol, distractions and tiredness. A faster speed increases both thinking  distance, increasing the total stopping distance.

<h2><em>I hope this is helpful. Would appreciate if you add me as brainliest.</em></h2>
7 0
4 years ago
Removing an electron from a neutral atom will result in an atom that?
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Removing an electron from a neutral atom will result in an atom that is positive.

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3 years ago
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4 years ago
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You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is
madreJ [45]

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book(m_0)=1.7 kg

height(h)=1 m

time taken=0.64 s

h=ut+frac{at^2}{2}

1=0+\frac{a(0.64)^2}{2}

a=4.88 m/s^2and [tex]a=\alpha r

where \alphais angular acceleration of pulley

4.88=\alpha \times 5.2\times 10^{-2}

\alpha =93.84 rad/s^2

And Tension in Rope

T=m(g-a)

T=1.7\times (9.8-4.88)

T=8.364 N

and Tension will provide Torque

T\times r=I\cdot \alpha

8.364\times 5.2\times 10^{-2}=I\times 93.84

I=0.463\times 10^{-2} kg-m^2

I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2

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4 0
3 years ago
Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compr
AnnZ [28]

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

8 0
3 years ago
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