Question

A load of 50N attached to a spring hanging vertically stretches the spring is 5cm . The spring is now placed horizontally on a table and stretched 11cm . What force is required to stretch the spring?

Answer 1

When the spring is now placed horizontally on a table and stretched 11cm then the force required to stretch the spring would be 110 N.

What is the spring constant?

The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.

The mathematical relation for calculating the spring constant is as follows

F = - Kx

where F represents the Force

x represents the amount of stretch in the spring

K represents the value of the spring constant

For the given problem that a load of 50N attached to a spring hanging vertically stretches the spring is 5cm

F= 50 N and x = 5 cm

K = F/x

  =50/5 N/ cm

  =10 N / cm

The spring constant for the spring is 10 N/ cm

Now the spring is placed horizontally on a table and stretched 11cm

by using the same formula we used earlier to calculate the spring constant

K = F/x

As we calculated the value of the spring constant (K) as 10 N / cm

by substituting K=10 N / cm and  x =11 cm

10 =F/11

F = 110 N

Thus, a force of 110 N force is required to stretch the spring when it is placed horizontally

Learn more about spring constant from here

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