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d1i1m1o1n [39]
3 years ago
14

A single output device has failed while the remainder of the PLC system is functioning normally The indicator light on the outpu

t module indicates that a signal is sent to the output point where the device is connected. You would now:
a) trace the circuit back through the logic to locate the inputs.

b) use a programming terminal to call up the rung that controls the output to see if the output coil is on.

c) check the point where the output device's field wiring is connected to the output rack.

d) check the input modules for short-circuit conditions.
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

check the point where the output device's field wiring is connected to the output rack. ( C )

Explanation:

Given that an indicator light on the output module is indicating that a signal has been sent to the output point where the failed single output device is connected , the best line of action to properly indicate the output device that has filed in the PLC system, is to check the point where the output device's field wiring is connected to the output rack in the PLC system.

A PLC system is a computer control system ( especially Industrial ) that helps in the monitoring the states of input and output devices in an industry.

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f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected
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Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

Weight=\frac{E_M-r_f}{A\sigma_M^2}

For the equity, here as

  • Weight is percentage of the equity which is to be calculated
  • {E_M-r_f} is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
  • A is the risk aversion factor which is given as 4.
  • \sigma_M is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%

So the weight of equity is 48.94%.

Now the weight of T bills is given as

Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\

So  the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0
3 years ago
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Answer:

V(t)= 240V* H(t-5)

Explanation:

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H(t) =1 \quad t\geq 0\\H(t) =0 \quad t

so we see that the Heaviside function "switches on" whent=0, and remains switched on when t>0

If we want our heaviside function to switch on when t=5, we need the argument to the heaviside function to be 0 when t=5

Thus we define a function f:

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The -5 term inside the heaviside function makes sure to displace the function 5 units to the right.

Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. (H(t-5) =1 when t\geq 5, so it becomes just a 1, which we can safely ignore.)

Therefore our final result is:

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I have made a sketch for you, and added it as attachment.  

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