All categories

3 years ago

7. What is the maximum amount of NaCl that can be dissolved (in 100g of water) at 90°C?

Chemistry

2 answers:

jeka943 years ago

8 0

Answer:

Maximum amount of NaCl that can be Dissolved in 100g of water at 90'C

Explanation:

In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C . So, at 80∘C , you will have an unsaturated solution if you dissolve less than 40 g of sodium chloride, and a saturated solution if you dissolve about 40 g of sodium chloride

kozerog [31]3 years ago

5 0

Answer:

The maximum amount of NaCl that can be Dissolved in 100g of water at 90'C

Explanation:

In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C . So, at 80∘C, you will have an unsaturated solution if you dissolve less than 40 g of sodium chloride, and a saturated solution if you dissolve about 40 g of sodium chloride.

You might be interested in

3. Which one is part of the kinetic molecular theory? Yes = part of KMT, No = not part

lidiya [134]

Explanation:

a. Average kinetic energy is directly proportional to absolute Kelvin temperature of a gas.

Yes

b. There are no attractive forces and repulsive forces between gas molecules.

Yes

C. Atoms are neither created nor destroyed by ordinary chemical reactions.

d. The volume occupied by all of the gas molecules in a container is negligible compared to the volume of the container

Yes

The kinetic molecular theory is one of such theories used to explain the forces between molecules and the energy they posses.

According to the theory;

The temperature of gas is proportional to the average kinetic energy.
Molecules are independent of one another and the force of attraction and repulsion between them is negligible.
volume occupied by gases is negligible compared to the volume of the container.

Law of conservation of matter states that "atoms are neither created nor destroyed by ordinary chemical reactions".

learn more:

Kinetic molecular theory brainly.com/question/12362857

#learnwithBrainly

6 0

4 years ago

Which element would lose electrons during ionic bonding choose all that apply

yawa3891 [41]

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

7 0

3 years ago

Explain why photosynthesis and cellular respiration are the “real circle of life”

BabaBlast [244]

Explanation:Photosynthesis is important because the earth and all of the creatures in the sea and land need the plants to be able to feed themselves with the help of the sun and with cellular respiration, those plants are able to take in the carbon dioxide that we give and make into oxygen with we need. there fore without them we would not be able to exist.

4 0

3 years ago

What is chlorine's atomic number and mass

makkiz [27]

$\red{⭐hello my \: friend!}$

chlorine's atomic number and mass :

35,453 u

$\blue{⭐have good studies!}$

☝️follow the rules of brainly!

8 0

3 years ago

What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N

Citrus2011 [14]

<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis
Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.68873 \ g \ Mg_3N_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

8 0

3 years ago