Answer:
3.01 L
Explanation:
V
1
: 2.75L
T
1
:
18
∘
C
V
2
: ?
T
2
:
45
∘
C
If you know your gas laws, you have to utilize a certain gas law called Charles' Law:
V
1
T
1
=
V
2
T
2
V
1
is the initial volume,
T
1
is initial temperature,
V
2
is final volume,
T
2
is final temperature.
Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.
Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:
2.75
291
=
V
2
318
By cross multiplying, we have...
291
V
2
= 874.5
Dividing both sides by 291 to isolate
V
2
, we get...
V
2
= 3.005...
In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.
Therefore,
V
2
= 3.01 L
<span>Answer
is: mass of burned butane is 11.6 g.</span>
Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
m(butane)
= 50,0 g.
<span>
V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷
Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) :
n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) =
0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) =
0,2 mol.<span>
m(C</span>₄H₁₀) =
n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) =
0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) =
11,6 g.
Answer:
The mass of gas is 30.02 g.
Explanation:
Given data:
Volume of gas = 22.4 L
Density of gas = 1.34 g/L
Mass of gas = ?
Solution:
The given problem will be solved through density formula.
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
Now we will put the values in formula.
1.34 g/L = m /22.4 L
m = 1.34 g/L × 22.4 L
m = 30.02 g
The mass of gas is 30.02 g.
We use a process called electrolysis to break apart water molecules into hydrogen and oxygen. Meaning electrolysis use an electrical current to split the molecule apart
Since it is stated that nitrogen is the limiting reactant (sometimes called limiting reagent), you only have to worry about the amount of nitrogen since we know that there is excess silicon.
Since this is a stoichiometry question, the first thing to do is turn the mass of nitrogen gas into moles by dividing the mass of nitrogen gas by its molar mass. (14.33g)/(28g/mol)=0.5118mol nitrogen gas. Then you have to convert moles of nitrogen gas to moles of silicon nitride by using the fact that 2 moles of nitrogen gas turn into 1 mole of silicon nitride (i got that ratio from the chemical equation given). (0.511mol N₂)x(1mol Si₃N₄/2mol N₂)=0.2555mol Si₃N₄. Know you just need to find the mass of silicon nitride by multiplying the number of moles of silicon nitride by its molar mass. (0.2555mol)x(140g/mol)=35.85g
Therefore the amount of silicon nitride produced from this reaction 35.85g.
I hope this helps
