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ElenaW [278]
3 years ago
9

7. What is the maximum amount of NaCl that can be dissolved (in 100g of water) at 90°C?

Chemistry
2 answers:
jeka943 years ago
8 0

Answer:

Maximum amount of NaCl that can be Dissolved in 100g of water at 90'C

Explanation:

In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C . So, at 80∘C , you will have an unsaturated solution if you dissolve less than 40 g of sodium chloride, and a saturated solution if you dissolve about 40 g of sodium chloride

kozerog [31]3 years ago
5 0

Answer:

The maximum amount of NaCl that can be Dissolved in 100g of water at 90'C

Explanation:

In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C . So, at 80∘C, you will have an unsaturated solution if you dissolve less than 40 g of sodium chloride, and a saturated solution if you dissolve about 40 g of sodium chloride.

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2. A balloon full of air has a volume of 2.75 L at a temperature of 18°C. What is the balloon's volume
Sphinxa [80]

Answer:

3.01 L

Explanation:

V

1

: 2.75L

T

1

:  

18

∘

C

V

2

: ?

T

2

:  

45

∘

C

If you know your gas laws, you have to utilize a certain gas law called Charles' Law:

V

1

T

1

=

V

2

T

2

V

1

is the initial volume,  

T

1

is initial temperature,  

V

2

is final volume,  

T

2

is final temperature.

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:

2.75

291

=

V

2

318

By cross multiplying, we have...

291

V

2

= 874.5

Dividing both sides by 291 to isolate  

V

2

, we get...

V

2

= 3.005...

In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.

Therefore,  

V

2

= 3.01 L

5 0
4 years ago
Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) = 0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) = 11,6 g.

5 0
4 years ago
The volume of a gas sample is 22.4 liters at STP. The density of the gas is 1.34 grams per liter.
lozanna [386]

Answer:

The mass of gas is 30.02 g.

Explanation:

Given data:

Volume of gas = 22.4 L

Density of gas = 1.34 g/L

Mass of gas = ?

Solution:

The given problem will be solved through density formula.

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

Now we will put the values in formula.

1.34 g/L = m /22.4 L

m = 1.34 g/L × 22.4 L

m = 30.02 g

The mass of gas is 30.02 g.

8 0
4 years ago
What does flame do to the separated Hydrogen and Oxygen that made up the water?
Dovator [93]
We use a process called electrolysis to break apart water molecules into hydrogen and oxygen. Meaning electrolysis use an electrical current to split the molecule apart
5 0
3 years ago
Read 2 more answers
38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen
REY [17]
Since it is stated that nitrogen is the limiting reactant (sometimes called limiting reagent), you only have to worry about the amount of nitrogen since we know that there is excess silicon.
Since this is a stoichiometry question, the first thing to do is turn the mass of nitrogen gas into moles by dividing the mass of nitrogen gas by its molar mass.  (14.33g)/(28g/mol)=0.5118mol nitrogen gas.  Then you have to convert moles of nitrogen gas to moles of silicon nitride by using the fact that 2 moles of nitrogen gas turn into 1 mole of silicon nitride (i got that ratio from the chemical equation given).  (0.511mol N₂)x(1mol Si₃N₄/2mol N₂)=0.2555mol Si₃N₄.  Know you just need to find the mass of silicon nitride by multiplying the number of moles of silicon nitride by its molar mass.  (0.2555mol)x(140g/mol)=35.85g
Therefore the amount of silicon nitride produced from this reaction 35.85g.

I hope this helps
3 0
3 years ago
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