Which is not a device for reproducing sound?

If a 15-ohm resistor is connected in parallel with a 30 ohm-resistor, the equivalent resistance is?

Bad White [126]

Answer:

Explanation:

in parallel combination equivalent resistence =

1/R=1/R1 + 1/R2

1/2=1/15+1/30

1/2=1*2+1*1/30

1/R=3/30

R*3=30*1

R=30/3

R=10 ohm

8 0

3 years ago

Read 2 more answers

PLEASE HELP I NEED TO SUBMIT THIS BEFORE MIDNIGHT!!!!!!!!!!!!!

Aloiza [94]

The Ohio Constitution lays out a three-part government with legislative, executive, and judicial branches just like the US Constitution. But the Ohio Constitution incorporates more elements of direct democracy and has a stronger legislative branch relative to the executive. Hopes this helps!

6 0

3 years ago

A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55

Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

$v_{0x} = 35 m/s$

The final velocity has an x and a y component:

$v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s$

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

$J = dp= m*dv$

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

$dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s$

Finally, substitute into the equation

$J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s$

J = 12.32kg*m/s

8 0

3 years ago

Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30

vekshin1

66.7 Watts

Explanation:

Let $R_{1}=1.0$ ohms, $R_{2}=3.0$ ohms and $R_{3}=6.0\:$ ohms. Since $R_{2}$ and $R_{3}$ are in parallel, their combined resistance $R_{23}$ is given by